将 PHP 中的变量从一个文件传递到另一个文件

问题描述

这是我的代码.现在我如何在另一个文件中使用 $pubname.

So this is my code. Now how do I use $pubname in another file.

mysqli_select_db($connect,"membership");
$retname = "select username from users where email='$globalname' limit 1";
$rn = mysqli_query($connect,$retname) or die(mysqli_error($connect));
$name = mysqli_fetch_array($rn);
    //connecting for mathcing username with fullname and displaying it
$pubname = mysqli_real_escape_string($name['username']);

include('profile.php');

echo $pubname;

还有这个代码安全吗?我这样做了......还没有工作.

and also is this code secure? I did that...does not work yet.

推荐答案

包含您希望变量可在其中访问的文件，就像这样

Include the file you would like the variable to be accessible within, like so

include('somefile.php')

并且在该文件的顶部您可能需要放置类似[取决于服务器配置]

and at the top of that file you might need put something like [depending on server configurations]

global $pubname

但在大多数情况下，您不需要这样做.

But in most cases you would not need to do this.

关于安全性，根据 $pubname 的设置方式，您的查询可能会或可能不会容易受到 sql 注入.

In regards to security, depending on how $pubname is set, your query may or may not be prone to sql injection.

注意:还有其他方法可以include() 文件，例如include_once()、require() 和require_once()，来自 php.net:

Note: There are other means to include() files such as include_once(), require() and require_once(), from php.net:

以下文档也适用要求().这两个构造是除了他们如何处理失败.include() 产生一个警告而 require() 导致致命错误.换句话说，使用require() 如果你想要一个丢失的文件停止处理页面.include() 不会这样，无论如何，脚本将继续.一定要有合适的include_path 设置也是如此.是警告需要解析错误文件不会导致处理停止在 PHP 4.3.5 之前的 PHP 版本中.从这个版本开始，它确实如此.

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