问题描述
我正在使用以下代码...
I'm using the following code...
169: const char *title = Title.c_str();
170: glutCreateWindow(title);
... Valgrind 给了我以下内容...
... Valgrind gives me the following ...
==28841== Conditional jump or move depends on uninitialised value(s)
==28841== at 0x6FF7A4C: (within /usr/lib64/libGLcore.so.180.44)
==28841== by 0x6FF81F7: (within /usr/lib64/libGLcore.so.180.44)
==28841== by 0x7289B36: (within /usr/lib64/libGLcore.so.180.44)
==28841== by 0x728A757: _nv000133gl (in /usr/lib64/libGLcore.so.180.44)
==28841== by 0x4EAB9E9: (within /usr/lib64/libGL.so.180.44)
==28841== by 0x4EAEA81: (within /usr/lib64/libGL.so.180.44)
==28841== by 0x4EB1D81: (within /usr/lib64/libGL.so.180.44)
==28841== by 0x4EA782B: glXCreateNewContext (in /usr/lib64/libGL.so.180.44)
==28841== by 0x54DF9AA: fgOpenWindow (in /usr/lib64/libglut.so.3.8.0)
==28841== by 0x54DE062: fgCreateWindow (in /usr/lib64/libglut.so.3.8.0)
==28841== by 0x54DF300: glutCreateWindow (in /usr/lib64/libglut.so.3.8.0)
==28841== by 0x4146CE: vimrid::glut::GlutApplication::Init() (GlutApplication.cpp:170)
但是什么是未初始化的?title 变量用 Title.c_str() 的值初始化，Title 是一个类成员，在构造函数成员初始化列表中初始化...
But what is uninitialized? The title variable is initialized with the value of Title.c_str() and Title is a class member which is initialized in the constructor member initialization list...
class VimridApplication
{
// ...
public:
std::string Title;
// ...
}
VimridApplication::VimridApplication() :
Title("Untitled VimridApplication")
{
// ...
}
class GlutApplication : public VimridApplication
{
// ...
}
推荐答案
Valgrind 带有一些默认的错误抑制，但这可能不包括 libCLcore.
Valgrind comes with some default error suppression, but that probably does not cover libCLcore.
错误检查工具可检测基础库中的许多问题，例如 GNU C 库和 X11 客户端库，这些库预装在您的 GNU/Linux 系统上.您无法轻松修复这些错误，但您不想看到这些错误(是的，有很多！)因此 Valgrind 在启动时读取要抑制的错误列表../configure 脚本在系统构建时会创建一个默认的抑制文件.
您可以创建自己的错误抑制您知道与您的代码无关.
You can create your own error suppressions that you know are irrelevant to your code.
这篇关于为什么 Valgrind 不喜欢我对 glutCreateWindow 的使用?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！