本文介绍了PHP:获得两个多维数组之间的差异的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有两个数组
$a1= array(
array('a'=>1,'b'=>2, 'c'=>3), // similar to $a2[0]
array('a'=>3,'b'=>4, 'c'=>5), // similar to $a2[1]
array('a'=>9,'b'=>6, 'c'=>9)
);
$a2= array(
array('a'=>1,'b'=>2, 'c'=>3),
array('a'=>3,'b'=>4, 'c'=>5),
array('a'=>5,'b'=>6, 'c'=>7),
array('a'=>11,'b'=>4, 'c'=>13),
array('a'=>14,'b'=>6, 'c'=>3)
);
我想要结果数组不具有
$arrayResult= array(
array('a'=>9,'b'=>6, 'c'=>9),// from $a1[3]
array('a'=>5,'b'=>6, 'c'=>7),// from $a2[2]
array('a'=>11,'b'=>4, 'c'=>13),// from $a2[3]
array('a'=>14,'b'=>6, 'c'=>3)// from $a2[4]
);
我尝试了array_udiff,也尝试了单独的功能,但是我无法正确地进行操作。 / p>
I have tried array_udiff, and also separate function but I'm unable to get the right thing.
推荐答案
Hmm快速解决方案,未优化
Hmm fast solution, not optimized
$result = array();
foreach($a1 as $va1) {
$found = false;
foreach($a2 as $va2) {
$x = array_diff($va1, $va2);
if (empty($x)) {
$found = true;
}
}
if (!$found) {
$result[] = $va1;
}
}
foreach($a2 as $va2) {
$found = false;
foreach($a1 as $va1) {
$x = array_diff($va2, $va1);
if (empty($x)) {
$found = true;
}
}
if (!$found) {
$result[] = $va2;
}
}
var_dump($result);
编辑:略有优化(取消了之前找到的值):
A little optimized (unseting values that were found before):
$a1= array(
array('a'=>1,'b'=>2, 'c'=>3), // similar to $a2[0]
array('a'=>3,'b'=>4, 'c'=>5), // similar to $a2[1]
array('a'=>9,'b'=>6, 'c'=>9)
);
$a2= array(
array('a'=>1,'b'=>2, 'c'=>3),
array('a'=>3,'b'=>4, 'c'=>5),
array('a'=>5,'b'=>6, 'c'=>7),
array('a'=>11,'b'=>4, 'c'=>13),
array('a'=>14,'b'=>6, 'c'=>3)
);
$i=0;
$result = array();
foreach($a1 as $ka1 => $va1) {
$found = false;
foreach($a2 as $ka2 => $va2) {
$i++;
$x = array_diff($va1, $va2);
if (empty($x)) {
$found = true;
unset($a2[$ka2], $a1[$ka1]);
}
}
if (!$found) {
$result[] = $va1;
}
}
foreach($a2 as $ka2 => $va2) {
$found = false;
foreach($a1 as $ka1 => $va1) {
$i++;
$x = array_diff($va2, $va1);
if (empty($x)) {
unset($a2[$ka2], $a1[$ka1]);
$found = true;
}
}
if (!$found) {
$result[] = $va2;
}
}
var_dump($result);echo $i;
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