问题描述
我有这段代码(将所有排列的出现打印在字符串中)
I have this code (printing the occurrence of the all permutations in a string)
def splitter(str):
for i in range(1, len(str)):
start = str[0:i]
end = str[i:]
yield (start, end)
for split in splitter(end):
result = [start]
result.extend(split)
yield result
el =[];
string = "abcd"
for b in splitter("abcd"):
el.extend(b);
unique = sorted(set(el));
for prefix in unique:
if prefix != "":
print "value " , prefix , "- num of occurrences = " , string.count(str(prefix));
我要打印字符串可变项中所有出现的排列.
I want to print all the permutation occurrence there is in string varaible.
因为排列的长度不同,所以我想固定宽度并以一种不错的方式打印它,而不是这样:
since the permutation aren't in the same length i want to fix the width and print it in a nice not like this one:
value a - num of occurrences = 1
value ab - num of occurrences = 1
value abc - num of occurrences = 1
value b - num of occurrences = 1
value bc - num of occurrences = 1
value bcd - num of occurrences = 1
value c - num of occurrences = 1
value cd - num of occurrences = 1
value d - num of occurrences = 1
如何使用format
来做到这一点?
How can I use format
to do it?
我找到了这些帖子,但与字母数字字符串的配合不太好:
I found these posts but it didn't go well with alphanumeric strings:
推荐答案
编辑2013-12-11 -此答案非常老.它仍然是正确和正确的,但是关注此问题的人们应该更喜欢新格式语法.
EDIT 2013-12-11 - This answer is very old. It is still valid and correct, but people looking at this should prefer the new format syntax.
您可以像这样使用字符串格式:
>>> print '%5s' % 'aa'
aa
>>> print '%5s' % 'aaa'
aaa
>>> print '%5s' % 'aaaa'
aaaa
>>> print '%5s' % 'aaaaa'
aaaaa
基本上:
-
%
字符通知python,它将必须用某些东西代替令牌 -
s
字符通知python令牌将是一个字符串 -
5
(或您想要的任何数字)会通知python在字符串中填充最多5个字符.
- the
%
character informs python it will have to substitute something to a token - the
s
character informs python the token will be a string - the
5
(or whatever number you wish) informs python to pad the string with spaces up to 5 characters.
在您的特定情况下,可能的实现方式如下:
In your specific case a possible implementation could look like:
>>> dict_ = {'a': 1, 'ab': 1, 'abc': 1}
>>> for item in dict_.items():
... print 'value %3s - num of occurances = %d' % item # %d is the token of integers
...
value a - num of occurances = 1
value ab - num of occurances = 1
value abc - num of occurances = 1
侧注::想知道您是否知道 itertools
模块.例如,您可以使用以下命令在一行中获取所有组合的列表:
SIDE NOTE: Just wondered if you are aware of the existence of the itertools
module. For example you could obtain a list of all your combinations in one line with:
>>> [''.join(perm) for i in range(1, len(s)) for perm in it.permutations(s, i)]
['a', 'b', 'c', 'd', 'ab', 'ac', 'ad', 'ba', 'bc', 'bd', 'ca', 'cb', 'cd', 'da', 'db', 'dc', 'abc', 'abd', 'acb', 'acd', 'adb', 'adc', 'bac', 'bad', 'bca', 'bcd', 'bda', 'bdc', 'cab', 'cad', 'cba', 'cbd', 'cda', 'cdb', 'dab', 'dac', 'dba', 'dbc', 'dca', 'dcb']
,通过将combinations
与count()
结合使用,您可以得到出现的次数.
and you could get the number of occurrences by using combinations
in conjunction with count()
.
这篇关于如何打印固定宽度的字符串?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!