如何使用C#通过Function调用EventHandler?

问题描述

我正在研究Some Project，现在我遇到了一些问题，问题是
我有一个EventHandler和一个Function.我想通过该函数调用该EventHandler.调用函数到函数很容易，但是我不知道如何通过函数调用EventHandler.请帮忙.

预先感谢:)

Hi,

Hi, I am working on Some Project, and now i am stuck with some issue, and the issue is
I have one EventHandler and one Function. I wants to call that EventHandler through that function. Calling function to function is easy but i dont know how to call a EventHandler through Function. Please Help.

thanks in advance:)

推荐答案

private void btnSearch_Click(object sender, EventArgs e)
{
    int rowIndex = -1;
            bool found = false;

            dgvProjects.SelectionMode = DataGridViewSelectionMode.FullRowSelect;
            try
            {
                //Set a string to search for
                int searchValue = int.Parse(tbSearchValue.Text);

                foreach (DataGridViewRow row in dgvProjects.Rows)
                {
                    int compareValue = int.Parse(row.Cells[2].Value.ToString());

                    if (compareValue.Equals(searchValue))
                    {
                        found = true;
                        rowIndex = row.Index;
                        dgvProjects.Rows[row.Index].Selected = true;
                        dgvProjects.FirstDisplayedScrollingRowIndex = rowIndex;
                        break;
                    }
                }

                if (!found)
                    MessageBox.Show("Project number not found.\n\nBe sure you're searching for the right project number.", "Project not found",
                        MessageBoxButtons.OK, MessageBoxIcon.Exclamation);
            }
            catch (FormatException)
            {
                MessageBox.Show("Your input is not a number.", "Input Error",
                    MessageBoxButtons.OK, MessageBoxIcon.Error);
            }
}

现在，我想在另一个函数中调用此代码(在我的示例中为另一个EventHandler，但这是相同的想法).因此，我将此代码复制到一个新函数中:

Now I want to call this code in an other function (In my example an other EventHandler, but it''s the same idea). So I copy this code to a new function:

private void SearchProject()
        {
            int rowIndex = -1;
            bool found = false;

            dgvProjects.SelectionMode = DataGridViewSelectionMode.FullRowSelect;
            try
            {
                //Set a string to search for
                int searchValue = int.Parse(tbSearchValue.Text);

                foreach (DataGridViewRow row in dgvProjects.Rows)
                {
                    int compareValue = int.Parse(row.Cells[2].Value.ToString());

                    if (compareValue.Equals(searchValue))
                    {
                        found = true;
                        rowIndex = row.Index;
                        dgvProjects.Rows[row.Index].Selected = true;
                        dgvProjects.FirstDisplayedScrollingRowIndex = rowIndex;
                        break;
                    }
                }

                if (!found)
                    MessageBox.Show("Project number not found.\n\nBe sure you're searching for the right project number.", "Project not found",
                        MessageBoxButtons.OK, MessageBoxIcon.Exclamation);
            }
            catch (FormatException)
            {
                MessageBox.Show("Your input is not a number.", "Input Error",
                    MessageBoxButtons.OK, MessageBoxIcon.Error);
            }
        }

然后，将之前的EventHandler代码更改为:

Then I change my previous EventHandler code to:

private void btnSearch_Click(object sender, EventArgs e)
{
    SearchProject();
}

现在我也可以在其他函数中调用SearchProject()了:

And now I can call SearchProject() in an other function too:

private void tbSearchValue_KeyDown(object sender, KeyEventArgs e)
{
    if (e.KeyCode == Keys.Enter)
        SearchProject();
}

protected void btnTest_Click(object sender, EventArgs e)

只需调用:

simply call:

btnTest_Click(null, null);

，但这仅在方法不使用这些参数中的任何一个时才有效.老实说，我仍然坚持以前的解决方案.

But this will only work when the method isn''t using either of these parameters. Honestly I''d still stick with my previous solution.

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