问题描述
我正在Xamarin中编写一个跨平台的解决方案,并且即将添加一个用于3rd-partyu集成的母项目(例如,其他仅希望使用Android上的意图与我的应用集成的Android缔约方)。
I'm writing a cross-platform solution in Xamarin, and am about to add a mother project for 3rd-partyu integration (e.g., other Android-parties that want to integrate with my app using intents on Android only).
但是我想保留我现在已经干净的跨平台设置,只需添加带有第3方集成代码的新Android类库即可。但是,我似乎无法在我的第3方集成项目中将自己的BroadcastReceiver包含在主要 Android应用程序项目中。
But I'd like to keep my cross-platform setup that I have now "clean" and simply add a new Android class library with the 3rd-party integration code. However, I cannot seem to get my BroadcastReceiver in my 3rd-party integration project to be included in my "main" android app project.
我已经添加了对第三方集成项目,但这显然还不够……我可以将我的BroadcastReceiver添加到主要的Android应用程序项目中,我猜这一切都很好,但我真的很想保留第三方集成项目党的东西孤立了,因为我可以很好地想象将来为其他目的添加其他集成机制,然后也希望将它们保留在另一个项目中。
I've added a reference to the 3rd-party integration project, but that's obviously not sufficient... I could just add my BroadcastReceiver in the main Android-app project instead, and that would be all well I guess, but I'd really like to keep the 3rd-party stuff isolated, since I could very well imaging adding other integration mechanisms in the future for other purposes and would then like to keep those in yet another project too.
任何建议?目前,在编译主要android-project时,第3方项目似乎甚至没有自动编译。
Any suggestions? Currently, the 3rd-party project does not even seem to get compiled automatically when compiling the main android-project.
编辑;
我的BroadcastReceiver使用属性推荐;
My BroadcastReceiver uses attributes as "recommended";
[BroadcastReceiver(Enabled = true)]
[IntentFilter(new[] { "se.millsys.integration.MyIntegrationIntent" })]
public class IntegrationBroadcastReceiver : BroadcastReceiver
{
private static string DEBUG_TAG = "IntegrationBroadcastReceiver";
public override void OnReceive(Context context, Intent intent)
{
}
}
推荐答案
假设设置如下:
Assuming this setup:
├── DroidMainApp
│ └── MyBroadcastReceiver (A Project level reference to DroidMainApp)
├── ADifferentApp
DroidMainApp
- 创建的Android应用程序模板
- 包名称的
com.sushihangover.toaster
- A template created Android app
- Package name of
com.sushihangover.toaster
- 创建的Android库项目模板
- 包含一个C#文件/类
- BroadcastReceiver是名为
com.sushihangover.toaster.receiver
- BroadcastReceiver已启用
已导出
- Template created Android Library Project
- Contains one C# file/class
- BroadcastReceiver is named
com.sushihangover.toaster.receiver
- BroadcastReceiver is
Enabled
andExported
DroidMainApp
[BroadcastReceiver(Name = "com.sushihangover.toaster.receiver", Enabled = true, Exported = true)]
public class Toaster : BroadcastReceiver
{
public override void OnReceive(Context context, Intent intent)
{
Toast.MakeText(context, "Go make some toast", ToastLength.Long).Show();
Log.Info("SO", "Go make some toast");
}
}
另一个应用程序调用DroidMainApp的 BroadcastReceiver
:
- 使用
明确的
意图 - Using an
Explicit
Intent
A Different App calling DroidMainApp's BroadcastReceiver
:
var toasterIntent = new Intent();
toasterIntent.SetClassName("com.sushihangover.toaster", "com.sushihangover.toaster.receiver");
var pendingIntent = PendingIntent.GetBroadcast(this, 0, toasterIntent, PendingIntentFlags.CancelCurrent);
var alarmService = (AlarmManager)GetSystemService(Context.AlarmService);
alarmService.SetRepeating(AlarmType.Rtc, 1000, 60000, pendingIntent);
这篇关于如何在另一个项目Xamarin项目中包含BroadcastReceiver?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!