展平一个可迭代的迭代

问题描述

如何编写 function 来返回嵌套在可迭代对象中的每个值?

How can I write function which should return every value nested in an iterable?

以下是我要完成的任务的示例:

Here's an example of what I'm trying to accomplish:

for i in function([1, 2, [3, 4, (5, 6, 7), 8, 9], 10]):
    print(i, end=' ')

预期输出:

1 2 3 4 5 6 7 8 9 10

推荐答案

Python 2 用户为此任务内置了:

Python 2 users have a built-in for this task:

from compiler.ast import flatten

不幸的是，它已在 python 3 中删除.不过你可以自己滚动:

Unfortunately, it has been removed in python 3. You can roll your own though:

from collections.abc import Iterable

def flatten(collection):
    for x in collection:
        if isinstance(x, Iterable) and not isinstance(x, (str, bytes)):
            yield from flatten(x)
        else:
            yield x

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