如何使用C#舍入两个十进制数字

问题描述

大家好，

我将两个小数点四舍五入，

到目前为止我尝试过的地方:

Hi guys,

I was rounding up the two decimal numbers,

where i tried so far:

int amt = Convert.ToInt32(Math.Round((conc * vol) / 1000, 2));
txtamt.Text = amt.ToString();

但是，如果数字为2.5，则仅给出结果2，但
我正在寻找3

谁能帮助我.

谢谢

but, if the number is 2.5,it is giving only result as 2, but
i''m looking for 3

Can any one plzzz help me.

thanks

推荐答案

int amt = (int)Math.Round((conc * vol) / 1000, MidpointRounding.AwayFromZero);

MidpointRounding.AwayFromZero确保输入的是2.5，例如，得到3.

The MidpointRounding.AwayFromZero makes sure that you get, for example, 3 if the input is 2.5.

double amt = Convert.ToDouble(Math.Round(((conc * vol) / 1000), 2));
                decimal i = decimal.Round(Convert.ToDecimal(amt), MidpointRounding.AwayFromZero);
                txtamt.Text = i.ToString();

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