问题描述
我的问题很简单.我有一个 try/except
代码.在 try 中,我尝试了一些 http 请求,而在 except 中,我有几种方法来处理我遇到的异常.
My problem is very simple.I have a try/except
code. In the try I have some http requests attempts and in the except I have several ways to deal with the exceptions I'm getting.
现在我想在我的代码中添加一个时间参数.这意味着尝试只会持续n"秒.否则用except捕捉它.
Now I want to add a time parameter to my code. Which means the try will only last for 'n' seconds. otherwise catch it with except.
在自由语言中,它会显示为:
In free language it would appear as:
try for n seconds:
doSomthing()
except (after n seconds):
handleException()
这是中间代码.不是函数.我必须抓住超时并处理它.我不能只是继续代码.
this is mid-code. Not a function. and I have to catch the timeout and handle it. I cannot just continue the code.
while (recoveryTimes > 0):
try (for 10 seconds):
urllib2.urlopen(req)
response = urllib2.urlopen(req)
the_page = response.read()
recoveryTimes = 0
except (urllib2.URLError, httplib.BadStatusLine) as e:
print str(e.__unicode__())
print sys.exc_info()[0]
recoveryTimes -= 1
if (recoveryTimes > 0):
print "Retrying request. Requests left %s" %recoveryTimes
continue
else:
print "Giving up request, changing proxy."
setUrllib2Proxy()
break
except (timedout, 10 seconds has passed)
setUrllib2Proxy()
break
我需要的解决方案是 try (for 10 seconds)
和 except (timeout, after 10 seconds)
The solution I need is for the try (for 10 seconds)
and the except (timeout, after 10 seconds)
推荐答案
查看文档
import urllib2
request = urllib2.Request('http://www.yoursite.com')
try:
response = urllib2.urlopen(request, timeout=4)
content = response.read()
except urllib2.URLError, e:
print e
如果您想捕获更具体的错误,请查看此帖子
If you want to catch more specific errors check this post
或替代请求
import requests
try:
r = requests.get(url,timeout=4)
except requests.exceptions.Timeout as e:
# Maybe set up for a retry
print e
except requests.exceptions.RequestException as e:
print e
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