问题描述
我正试图从麦克风上获得分贝,并且到处都在寻找如何正确执行分贝的方法,但是它们似乎没有用.
I'm trying to get the decibels from the microphone and have looked everywhere how to correctly do it but they don't seem to work.
我得到这样的振幅
public class SoundMeter {
static final private double EMA_FILTER = 0.6;
private MediaRecorder mRecorder = null;
private double mEMA = 0.0;
public void start() {
if (mRecorder == null) {
mRecorder = new MediaRecorder();
mRecorder.setAudioSource(MediaRecorder.AudioSource.MIC);
mRecorder.setOutputFormat(MediaRecorder.OutputFormat.THREE_GPP);
mRecorder.setAudioEncoder(MediaRecorder.AudioEncoder.AMR_NB);
mRecorder.setOutputFile("/dev/null/");
try {
mRecorder.prepare();
} catch (IllegalStateException | IOException e) {
e.printStackTrace();
}
mRecorder.start();
mEMA = 0.0;
}
}
public void stop() {
if (mRecorder != null) {
mRecorder.stop();
mRecorder.release();
mRecorder = null;
}
}
public double getTheAmplitude(){
if(mRecorder != null)
return (mRecorder.getMaxAmplitude());
else
return 1;
}
public double getAmplitude() {
if (mRecorder != null)
return (mRecorder.getMaxAmplitude()/2700.0);
else
return 0;
}
public double getAmplitudeEMA() {
double amp = getAmplitude();
mEMA = EMA_FILTER * amp + (1.0 - EMA_FILTER) * mEMA;
return mEMA;
}
}
然后在我的其他活动中,我调用getAmplitude方法,它返回振幅.要将其转换为分贝,我使用以下方法:
Then In my other activity I call the getAmplitude method an it returns the amplitude.To convert it to decibels I use this:
dB = 20 * Math.log10(soundMeter.getAmplitude() / 32767);
我已经为32767尝试了许多不同的值,但似乎没有一个给我一个现实的分贝答案.通常是负数,有时是无穷大.如果您知道如何正确找到分贝,请提供帮助.
Ive tried many different values in place for the 32767 but none of them seem to give me a realistic decibel answer. It's usually negative and sometimes -infinity. Please help if you know how to find decibels the right way.
推荐答案
getMaxAmplitude返回0到32767之间的数字.要将其转换为dB,您需要首先将其缩放为0到-1之间的值. 20 * log10(1)== 0
和 20 * log10(0)==-inf
.
getMaxAmplitude returns a number between 0 and 32767. To convert that to dB you need to first scale it to to a value between 0 and -1. 20*log10(1)==0
and 20*log10(0)==-inf
.
如果获取-inf,则只能是因为要将0传递给log函数.这很可能是因为您要进行整数除法.将分母更改为双精度以强制进行浮点除法.
If you're getting -inf then this can only be because you're passing 0 to the log function. This is most likely because you are doing integer division. Change the denominator to a double to force a floating point division.
double dB = 20*log10(x / 32767.0);
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