获取选择&在PHP中显示选定的选项

问题描述

我已经尝试了很多&搜索了很多，但我没有找到解决方案。

我有HTML代码

HTML

 < form id =program_modeaction =method =post> 
 < option>选择< / option> 
< option value =<？php echo $ vars ['url']？> pg / event_calendar / all<？php if（$ mode =='All'）echo'selected =选择'; ？>>所有< /选项> 
< option value =<？php echo $ vars ['url']？> pg / event_calendar / anytime<？php if（$ mode =='Online'）echo'selected =选择'; ？>>在线< /选项> 
< option value =<？php echo $ vars ['url']？> pg / event_calendar / offline<？php if（$ mode =='Offline'）echo'selected =选择'; ？>>离线< /选项> 
< / select> 
< / form> 
  

然后我想在php部分选中选项。

所以我写过像

PHP

  $ mode = $ _POST ['mode']; 
 var_dump（$ mode）; 
  

但我没有收到价值。我不想提交的东西。 Onchange只有它应该得到的价值。

解决方案

 < form id =program_modeaction = method =post> 
 < option>选择< / option> 
< option value =<？php echo $ vars ['url']？> pg / event_calendar / all<？php if（$ mode =='All'）echo'selected =选择'; ？>>所有< /选项> 
< option value =<？php echo $ vars ['url']？> pg / event_calendar / anytime<？php if（$ mode =='Online'）echo'selected =选择'; ？>>在线< /选项> 
< option value =<？php echo $ vars ['url']？> pg / event_calendar / offline<？php if（$ mode =='Offline'）echo'selected =选择'; ？>>离线< /选项> 
< / select> 
< / form> 
  

使用小jquery，您可以使用这个

 < script> 
函数val_changed（）
 {
 var mode = $（'＃mode'）。val（）; 
 
} 
< / script> 
  

I have tried a lot & searched a lot but i didn't found the solution.

I have HTML code

HTML

<form id="program_mode" action="" method="post">
        <select name="mode" id="mode">
            <option>Select</option>
            <option value="<?php echo $vars['url']?>pg/event_calendar/all" <?php if($mode == 'All') echo 'selected="selected"'; ?>>All</option>
            <option value="<?php echo $vars['url']?>pg/event_calendar/anytime" <?php if($mode == 'Online') echo 'selected="selected"'; ?>>Online</option>
            <option value="<?php echo $vars['url']?>pg/event_calendar/offline" <?php if($mode == 'Offline') echo 'selected="selected"'; ?>>Offline</option>
        </select>
        </form>

Then i want in php part the selected option.

So i have written like

PHP

$mode = $_POST['mode'];
var_dump($mode);

But i am not getting the value. The thing i dont want to submit. Onchange only it should get the value. Can it will be possible ?

解决方案

<form id="program_mode" action="" method="post">
    <select name="mode" id="mode" onchange="val_changed()">
        <option>Select</option>
        <option value="<?php echo $vars['url']?>pg/event_calendar/all" <?php if($mode == 'All') echo 'selected="selected"'; ?>>All</option>
        <option value="<?php echo $vars['url']?>pg/event_calendar/anytime" <?php if($mode == 'Online') echo 'selected="selected"'; ?>>Online</option>
        <option value="<?php echo $vars['url']?>pg/event_calendar/offline" <?php if($mode == 'Offline') echo 'selected="selected"'; ?>>Offline</option>
    </select>
    </form>

With little jquery you can do with this

    <script>
function val_changed()
        {
        var mode=$('#mode').val();

        }
</script>

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