在字典列表中组合相同键的值

问题描述

我有以下格式的字典列表:

I have a list of dictionaries in the following format:

foo = [
    {'a': 'x', 'b': 'y', 'c': 'z'},
    {'a': 'j', 'c': 'z'}
]

我想将此字典列表分组为一个字典，例如:

I want to group this list of dictionaries into a single dictionary, like:

bar = {
    'a': ['x', 'j'],
    'b': ['y', None],
    'c': ['z', 'z']
}

我目前所做的是，循环遍历 foo 中的所有 dicts 并创建一个键列表，然后再次循环以创建 bar.我想知道是否有更简单的方法来实现这一点.有人可以帮忙吗?

What I've currently done is, looping through all the dicts in foo and create a list of keys and then looping again over the same to create bar. I wonder whether there is a simpler way to accomplish this. Can anyone help?

推荐答案

bar = {
    k: [d.get(k) for d in foo]
    for k in set().union(*foo)
}

谷歌的东西:

• python 列表理解
• python 字典理解
• 巨蟒之星
• python 字典获取
• python 集合联合

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