在Swift数组中查找唯一值

问题描述

我正在建立一个项目，告诉我一段文本中的唯一单词.

I am building a project that tells me the unique words in a piece of text.

我有我的原始字符串 scriptTextView ，我已将每个单词添加到数组 scriptEachWordInArray

I have my orginal string scriptTextView which I have added each word into the array scriptEachWordInArray

我现在想创建一个名为 scriptUniqueWords 的数组，该数组仅包含在 scriptEachWordInArray

I would now like to create an array called scriptUniqueWords which only includes words that appear once (in other words are unique) in scriptEachWordInArray

因此，我希望我的scriptUniqueWords数组等于= ["Silent"，"Holy"].

So I'd like my scriptUniqueWords array to equal = ["Silent","Holy"] as a result.

我不想创建一个没有重复项的数组，而是创建一个仅具有一次出现一次的值的数组.

var scriptTextView = "Silent Night Holy Night"
var scriptEachWordInArray = ["Silent", "night", "Holy", "night"]
var scriptUniqueWords = [String]()

for i in 0..<scriptEachWordInArray.count {

    if scriptTextView.components(separatedBy: "\(scriptEachWordInArray[i]) ").count == 1 {
        scriptUniqueWords.append(scriptEachWordInArray[i])
        print("Unique word \(scriptEachWordInArray[i])")}

}

推荐答案

您可以使用NSCountedSet

let text = "Silent Night Holy Night"
let words = text.lowercased().components(separatedBy: " ")
let countedSet = NSCountedSet(array: words)
let singleOccurrencies = countedSet.filter { countedSet.count(for: $0) == 1 }.flatMap { $0 as? String }

现在singleOccurrencies包含["holy", "silent"]

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