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问题描述
我有一个页面网址,看起来像:
I have a page url, which looks like:
安装tomcat后7,当试图访问它时我得到了这个例外:
After installing tomcat 7, when trying to access it I got this exception:
/nodes/${param.id}/article/new?return=${param.return}
contains invalid expression(s): javax.el.ELException: The identifier [return] is not a valid Java identifier as required by section 1.19 of the EL specification (Identifier ::= Java language identifier). This check can be disabled by setting the system property org.apache.el.parser.SKIP_IDENTIFIER_CHECK to true.
任何想法我为什么会这样做?要修复它,我应该只在tomcat中更改此属性吗?
Any ideas why I get that? To fix it should I change this property in tomcat only?
推荐答案
return
是Java编程语言(tm)中的保留关键字。但幸运的是,有一种替代拼写。请尝试 param ['return']
。
return
is a reserved keyword in the Java Programming Language(tm). But luckily there is an alternative spelling. Try param['return']
instead.
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