在C ++中使用标准库函数名称作为标识符是否有效?

问题描述

考虑以下程序:

#include <cstdio>
int main()
{
    int printf=9;
    std::printf("%d",printf);
}

使用内置函数名称作为变量声明中的标识符是否可以?这个程序定义明确吗?我的意思是上述程序的行为定义得很好吗?我很好奇C ++标准是否允许使用标准函数名作为变量的标识符

Is it fine to use built in function name as an identifier in variable declaration? Is this well defined program? I mean is behaviour of above program well defined? I am curious to know whether the C++ standard allows to use standard function names as identifiers of variables

推荐答案

格式正确，因为 std :: printf 和 :: printf (也可能已经由< cstdio> ！声明了！)在与整数相同的作用域中声明，因此，在该块的持续时间内，此优先级会自动获得.

It's well-formed because neither std::printf nor ::printf (which may also have been declared by <cstdio>!) are declared in the same scope as your integer, which therefore takes automatic precedence for the duration of the block.

例如，您通常无法在名称空间范围内执行此操作

由于标准库中实体的名称不是固有保留的名称，因此定义明确:

It's well-defined because the names of entities in the standard library are not inherently reserved names:

[C ++ 14:17.6.4.3.2/1]:某些名称和函数签名集始终保留给实现:

[C++14: 17.6.4.3.2/1]: Certain sets of names and function signatures are always reserved to the implementation:

• 每个包含双下划线 _ _ 的名称或以下划线后跟大写字母(2.12)开头的名称将保留给实现以供任何使用.
• 以下划线开头的每个名称都保留给实现，以用作全局名称空间中的名称.

• Each name that contains a double underscore _ _ or begins with an underscore followed by an uppercase letter (2.12) is reserved to the implementation for any use.
• Each name that begins with an underscore is reserved to the implementation for use as a name in the global namespace.

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