C＃获取1个数据/ 20

本文介绍了C＃获取1个数据/ 20的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 您好！ 此代码中创建的文本文件并不好。我没有很好的价值观。 我想我的问题是关于这一行： Hello !The text file which is created in this code, is not good. I don't have the good values.I suppose my problem is about this line : float delta_x = (((nv_data [59].positions [frame] - nv_data [59].positions [frame - 1]).z) * 0.001f); 我认为需要： I think it takes : nv_data[59].positions[20]-nv_data[59].positions[19]nv_data[59].positions[40]-nv_data[59].positions[39]nv_data[59].positions[60]-nv_data[59].positions[59]... 或： or :nv_data[59].positions[20]-nv_data[59].positions[0]nv_data[59].positions[21]-nv_data[59].positions[1]nv_data[59].positions[22]-nv_data[59].positions[2]... 或： or :nv_data[59].positions[20]-nv_data[59].positions[19]nv_data[59].positions[21]-nv_data[59].positions[20]nv_data[59].positions[22]-nv_data[59].positions[21]... 而不是：（这就是我想要的） Instead of : (and it's it that I want)nv_data[59].positions[20]-nv_data[59].positions[0]nv_data[59].positions[40]-nv_data[59].positions[20]nv_data[59].positions[60]-nv_data[59].positions[40]... 我只想使用每一帧/ 20。 这里出现的代码部分： I want to use only each frame / 20 .Here the part of the code where it appears :void FixedUpdate() { delta_time += Time.deltaTime; if (frame < nv_data [0].positions.Length) { if ((frame % 20) == 0) { for (int k = 0; k < body.Length; ++k) { if (body [k] != null) { body [k].transform.localPosition = nv_data [k].positions [frame] / 1000; // This part is ok } else continue; } Debug.Log("Frame_animation : " + frame); // I have 1 frame / 20 : 0 , 20 , 40 , 60 , ... if (indice_3 < forces_dup.Length-1) { if (frame >= 20) { Debug.Log ("Frame_writer : " + frame); // I have 1 frame / 20 : 0 , 20 , 40 , 60 , ... float delta_x = (((nv_data [59].positions [frame] - nv_data [59].positions [frame - 1]).z) * 0.001f); // It's here that I think I have some problems vitesse = delta_x / Time.deltaTime; acceleration = (vitesse - ancienne_vitesse) / Time.deltaTime; ancienne_vitesse = vitesse; indice_3 ++; StreamWriter writer = new StreamWriter ("Masse-fois-Accelerations_FR_5Hz", true); using (writer) { writer.WriteLine (Time.time + "\t" + 80*acceleration + "\t" + forces_dup [indice_3].x); // Here I don't have the correct values for 80*acceleration } } } } frame++; } } 非常感谢您的帮助Thank you very much in advance for your help推荐答案 void FixedUpdate() { delta_time += Time.deltaTime; if (frame < nv_data [0].positions.Length) { if ((frame % 20) == 0) { for (int k = 0; k < body.Length; ++k) { if (body [k] != null) { body [k].transform.localPosition = nv_data [k].positions [frame] / 1000; } else continue; } if (indice_3 < forces_dup.Length-1) { if (frame >= 1) { float delta_z = (((nv_data [59].positions [frame] - nv_data [59].positions [frame - 20]).z) * 0.001f); vitesse = delta_z / (Time.deltaTime*20); acceleration = (vitesse - ancienne_vitesse) / (Time.deltaTime*20); ancienne_vitesse = vitesse; indice_3 ++; StreamWriter writer = new StreamWriter ("Masse-fois-Accelerations_FR_5Hz", true); using (writer) { writer.WriteLine (Time.time + "\t" + 80*acceleration + "\t" + forces_dup [indice_3].x); } } } } frame++; } 这篇关于C＃获取1个数据/ 20的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！