是否有可能从zipinputstream获得zipentry的输入流？

问题描述

我从另一个源接收ZipInputStream，我需要将第一个条目的InputStream提供给另一个源。

I'm receiving a ZipInputStream from another source, and I need to provide the first entry's InputStream to another source.

我希望能够这样做没有在设备上保存临时文件，但我知道获取单个条目的InputStream的唯一方法是通过ZipFile.getInputStream（entry），因为我有一个ZipInputStream而不是ZipFile，这是不可能的。

I was hoping to be able to do this without saving a temp file on a device, however the only way I know of getting an InputStream for an individual entry is via ZipFile.getInputStream(entry) and since I have a ZipInputStream and not a ZipFile, that is not possible.

所以我拥有的最佳解决方案是

So the best solution I have is

1. 将传入的InputStream保存到文件


2. 读取文件为ZipFile


3. 使用第一个条目的InputStream


4. 删除临时文件。

1. save incoming InputStream to a file
2. read file as ZipFile
3. use first entry's InputStream
4. delete temp file.

推荐答案

想通：

完全有可能，调用ZipInputStream .getNextEntry（）将InputStream定位在条目的开头，因此提供ZipInputStream相当于提供ZipEntry的InputStream。

it's entirely possible, the call to ZipInputStream.getNextEntry() positions the InputStream at the start of the entry and therefore supplying the ZipInputStream is the equivalent of supplying a ZipEntry's InputStream.

ZipInputStream是smart e没有处理条目的EOF下游，或者看起来如此。

the ZipInputStream is smart enough to handle the entry's EOF downstream, or so it seems.

p。

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