删除所有内容但保持匹配

问题描述

如果我有一个大文本，我需要只保留匹配的内容，我该怎么做?

If i have a big text, and i'm needind to keep only matched content, how can i do that?

例如，如果我有这样的文字:

For example, if I have a text like this:

asdas8Isd8m8Td8r
asdia8y8dasd
asd8is88n8gd
asd8t8od8lsdas
as9ea9ad8r1n88r8e87g6765ejasdm8x

并使用此正则表达式:[0-9]([az]) 将数字后的所有字母分组并替换为 \1 我将全部替换(数字)(letter) to (letter) (如果我想删除其余的并只保留匹配的字母)?...

And use this regex: [0-9]([a-z]) to group all letters after a number and replace with \1 i will repace all (number)(letter) to (letter) (And if i want to delete the rest and stay only with the letter matched)?...

将此文本转换为

ImTr
y
ing
tol
earnregex

如何用分组替换此文本并删除其余文本?

How can i replace this text with grouped and delete the rest?

如果我想删除所有但没有匹配的内容?在这种情况下，将文本转换为:

And if i want to delete all but no matched?In this case, converting the text to:

8I8m8T8r
8y8d
8i8n8g
8t8o8l
9e9a9r1n8r7g5e8x

我可以匹配所有不是 [0-9]([a-z]) 的吗?

Can i match all that is not [0-9]([a-z])?

谢谢！:D

推荐答案

您可以使用以下正则表达式:

You may use the following regex:

(?i-s)[0-9]([a-z])|.

替换为 (?{1}$1:).

要删除除不匹配之外的所有内容，请使用具有相同正则表达式的 (?{1}$0:) 替换.

To delete all but non-matched, use the (?{1}$0:) replacement with the same regex.

详情:

• (?i-s) - 内联修饰符打开不区分大小写模式并关闭 DOTALL 模式(. 与换行符不匹配)
• [0-9]([az]) - 一个 ASCII 数字和任何捕获到组 1 中的 ASCII 字母(以后用 $1 或 \1 来自字符串替换模式的反向引用)
• | - 或
• . - 除换行符以外的任何字符.

• (?i-s) - an inline modifier turning on case insensitive mode and turning off the DOTALL mode (. does not match a newline)
• [0-9]([a-z]) - an ASCII digit and any ASCII letter captured into Group 1 (later referred to with $1 or \1 backreference from the string replacement pattern)
• | - or
• . - any char but a line break char.

更换详情

• (?{1} - 条件替换的开始:如果第 1 组匹配，则...
  • $1 - 第 1 组的内容(如果使用 $0 反向引用，则为整个匹配)
  • : - 否则……什么都没有
  • (?{1} - start of the conditional replacement: if Group 1 matched then...
    • $1 - the contents of Group 1 (or the whole match if $0 backreference is used)
    • : - else... nothing

    这篇关于删除所有内容但保持匹配的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！