本文介绍了如何找出C ++/C中是否已填充指针数组的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
假设我有功能
其中pa从[0]填充到[100]或者pa仅填充为[0].
where pa is either populated from [0] to [100]ORpa is populated for [0] only.
我的功能执行以下操作:
My function does the following:
{
IF(pa是100的数组)则x [0到100] = pa [0到100]
IF (pa is an array of 100) THEN x[0 to 100] = pa[0 to 100]
ELSE x [0至100] = pa [0]
ELSE x[0 to 100] = pa[0]
}
推荐答案
问:foo()如何知道pa []是否为100的数组?
Q: How is foo() going to know whether pa[] is an array of 100?
通常，您必须告诉它.例如:
In general, you have to TELL it. For example:
void
foo (double *pa, int len)
{
if (len == 100)
...
else
...
但是，如果您使用C ++进行编码，则可以使用STL容器，例如矢量:
If you were coding in C++, however, you could use an STL container such as a vector:
void foo (vector<double> & pa)
{
if (pa.size() == 100)
...
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