Python日志记录:传播低于当前记录器级别的消息

问题描述

我想将特定级别和更高级别(例如INFO及更高)的特定记录器名称的消息记录到特定的日志处理程序(例如文件处理程序)，同时仍将所有日志消息发送到控制台. Python是2.7版.

I want to log messages of a specific logger name, of a certain level and higher (say INFO and up) to a specific log handler, say a file handler, while still getting all log messages to the console. Python is version 2.7.

到目前为止，我一直尝试创建两个记录器:

What I tried until now was to create two loggers:

• 根记录器
• 命名记录器

对于root记录器，我附加了logging.StreamHandler，并将日志级别设置为logging.DEBUG.

For the root logger, I attached a logging.StreamHandler, and set the log level to logging.DEBUG.

然后，我将处理程序附加到命名记录器，并将该记录器的级别设置为logging.INFO.

Then I attached a handler to the named logger and set level to logging.INFO for that logger.

现在我调用使用命名记录器的模块时，不再将DEBUG日志传播到根记录器.

When I now call my module, which uses the named logger, I do not get DEBUG logs propagated to the root logger any more.

注意:extraLogger在此处有一个 StreamHandler 来演示该问题.在生产代码中，我将使用 FileHandler

Note: the extraLogger has a StreamHandler here to demonstrate the issue. In my production code I'd use a FileHandler

import logging

def do_logging(turn):
    logger = logging.getLogger('extra')
    logger.info('some info turn %d' % turn)
    logger.debug('this is debug fudge turn %d' % turn)

rootLogger = logging.getLogger()
handler = logging.StreamHandler()
rootFormatter = logging.Formatter('root - %(levelname)s: %(msg)s')
handler.setFormatter(rootFormatter)
rootLogger.addHandler(handler)
rootLogger.setLevel(logging.DEBUG)

do_logging(1)

extraLogger = logging.getLogger('extra')
extraHandler = logging.StreamHandler()
extraFormatter = logging.Formatter('extra - %(levelname)s: %(msg)s')
extraHandler.setFormatter(extraFormatter)
extraLogger.addHandler(extraHandler)
extraLogger.setLevel(logging.INFO)

do_logging(2)

实际输出:

root - INFO: some info turn 1
root - DEBUG: this is debug fudge turn 1
extra - INFO: some info turn 2
root - INFO: some info turn 2

我想要的输出:

root - INFO: some info turn 1
root - DEBUG: this is debug fudge turn 1
extra - INFO: some info turn 2
root - INFO: some info turn 2
root - DEBUG: this is debug fudge turn 2

我怀疑自定义Filter在这种情况下会有所帮助，但我不知道如何...

I suspect that a custom Filter would be helpful in this case, but I do not know how...

推荐答案

您可以这样使用 robert的LevelFilter :

# Put the Filter on the Handler so only INFO and higher is handled
extraHandler.addFilter(LevelFilter(logging.INFO))

# Let the Logger process everything (so it can propagate records to root)
extraLogger.setLevel(logging.DEBUG)

---

import logging

class LevelFilter(logging.Filter):
    """
    https://stackoverflow.com/a/7447596/190597 (robert)
    """
    def __init__(self, level):
        self.level = level

    def filter(self, record):
        return record.levelno >= self.level

def do_logging(turn):
    logger = logging.getLogger('extra')
    logger.info('some info turn %d' % turn)
    logger.debug('this is debug fudge turn %d' % turn)

rootLogger = logging.getLogger()
handler = logging.StreamHandler()
rootFormatter = logging.Formatter('root - %(levelname)s: %(msg)s')
handler.setFormatter(rootFormatter)
rootLogger.addHandler(handler)
rootLogger.setLevel(logging.DEBUG)
do_logging(1)

extraLogger = logging.getLogger('extra')
extraHandler = logging.StreamHandler()
extraFormatter = logging.Formatter('extra - %(levelname)s: %(msg)s')
extraHandler.setFormatter(extraFormatter)
extraLogger.addHandler(extraHandler)

# Put the Filter on the Handler so only INFO and higher is handled
extraHandler.addFilter(LevelFilter(logging.INFO))

# Handle everything (so it can propagate to root)
extraLogger.setLevel(logging.DEBUG)
do_logging(2)

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