解析json时遇到意外的字符 | 解析json时遇到意外的字符

本文介绍了解析json时遇到意外的字符的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我使用以下代码反序列化了一个json Response：

 string data = response.Content; 
 
 //将其反序列化为包含每个键及其值的对象
 
 Dictionary< string，object> values = JsonConvert.DeserializeObject< Dictionary< string，object>>（data）; 
 
 
 TextBox1.Text = Convert.ToString（values [values]）;

但我收到的错误是：

Jsnon响应数据看起来像这样

我尝试过：

我试过使用以下代码解决它但它仍然给出相同的错误，

 var settings = new JsonSerializerSettings 
 {
 NullValueHandling = NullValueHandling.Ignore，
 MissingMemberHandling = MissingMemberHandling.Ignore 
}; 
 // var jsonModel = JsonConvert.DeserializeObject< Customer>（jsonString，settings）; 
 Dictionary< string，object> values = JsonConvert.DeserializeObject< Dictionary< string，object>>（data，settings）; 
 
 TextBox1.Text = Convert.ToString（values [values]）;

解决方案

I deserialized a json Response with the following code:

string data = response.Content;

 //Deserializing it into an object that will contain each of the keys and their values

Dictionary<string, object> values = JsonConvert.DeserializeObject<Dictionary<string, object>>(data);


TextBox1.Text = Convert.ToString(values["values"]);

But I get error that says:

The Jsnon Response Data Looks like this

What I have tried:

I tried using the following code to resolve it but it still give the same error,

var settings = new JsonSerializerSettings
                    {
                        NullValueHandling = NullValueHandling.Ignore,
                        MissingMemberHandling = MissingMemberHandling.Ignore
                    };
                   // var jsonModel = JsonConvert.DeserializeObject<Customer>(jsonString, settings);
                    Dictionary<string, object> values = JsonConvert.DeserializeObject<Dictionary<string, object>>(data, settings);

                    TextBox1.Text = Convert.ToString(values["values"]);

解决方案

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