在C ++中，我收到一条消息“错误:'void *'不是指向对象的指针类型".

问题描述

这是我的代码:

#include <iostream>
using namespace std;

int main()
{
   void *x;
   int arr[10];
   x = arr;
   *x = 23; //This is where I get the error
}

如您所见，代码非常简单.它只是创建一个空指针x，该指针指向数组"arr"的内存地址，并将整数23放入该内存地址.但是，当我对其进行编译时，会收到错误消息'void *'不是指针到对象的类型".当我使用'int'指针而不是void指针进行编译时，我没有收到任何错误或警告.我想知道为什么会收到此错误.

As you can see, the code is very simple. It just creates a void pointer x which points to the memory address of the array 'arr' and puts the integer 23 into that memory address. But when I compile it, I get the error message "'void*' is not a pointer-to-object type". When I use an 'int' pointer instead of a void pointer and then compile it, I don't get any errors or warnings. I wanna know why I get this error.

谢谢.

推荐答案

如编译器消息所述，void*不是指向对象类型的指针.这意味着您不能使用void*进行任何操作，除了将其显式转换回另一种指针类型. void*代表地址，但未指定其指向的内容的类型，因此您无法对其进行操作.

As the compiler message says, void* is not a pointer to object type. What this means is that you cannot do anything with void*, besides explicitly converting it back to another pointer type. A void* represents an address, but it doesn’t specify the type of things it points to, and at a consequence you cannot operate on it.

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