在 Java 中创建 Neo4j 关系

问题描述

我正在基于 no 在 java 类中创建独特的 neo4j 关系.数据库中的列值.Interface_Name"列的值将分配给每个关系.我的代码:

I am creating unique neo4j relationships in java class based on no. of column values in database.Value of column "Interface_Name" will be assigned to each relationship.My Code :

while (rs.next()){
    String rel = rs.getString("Interface_Name");
    GraphDatabaseService graphDb = new EmbeddedGraphDatabase("D://My Graph");
    Transaction tx = graphDb.beginTx();
    try {
        RelationshipType rel = DynamicRelationshipType.withName(rel); **//Gives error since rel is string**
        .....
        tx.success();
    }
}

如何根据数据库中的列值创建关系类型?在循环内部，应根据数据库值创建关系类型.

How can i create relationship Types based on Column values in DB?Inside while loop Relationship Types should get created according to DB values.

推荐答案

不创建节点就无法创建关系.您将需要一个开始节点和一个结束节点.另外，不要为遇到的每一列都创建一个新的 GraphDatabaseService.您的代码可能是这样的:

You can't create relationships without creating nodes. You'll need a start node and an end node. Also, don't create a new GraphDatabaseService for every column you encounter. Your code could be something like this:

GraphDatabaseService graphDb = new EmbeddedGraphDatabase("D://My Graph");
while (rs.next()){
    String rel = rs.getString("Interface_Name");
    try (Transaction tx = graphDb.beginTx()) {
         RelationshipType relType = DynamicRelationshipType.withName(rel);
         graphDb.createNode().createRelationshipTo(graphDb.createNode(), relType);
         tx.success();
    }
}

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