问题描述
我已经看到了一些关于这方面的问题，但没有一个我读了帮助我真正理解为什么我想要做的是失败。有一堆浮点值，他们有不同的精度。有些是0.1其他的是1.759374等，而我想格式化它们，所以他们都是+ 0.0000000E + 00的形式我试着做
pre > number ='％1.7f'％oldnumber
工作。我以为我说的是小数点后一位数字，后面是7位数字，但是它不起作用。我没有真正得到文档中的例子，这似乎甚至没有小数点前后的问题的困扰，我没有发现一个小数点修复前后的问题。 p>
现在，我知道我的一些数字是0.0437或类似的，我希望他们出现在4.3700000E-02之类的东西。我有点希望它能自己做E，但是如果不是我该怎么做？
下面是我的确切线：
RealValConv ='％1.7g'％struct.unpack（'！f'，RealVal.decode（'hex'）） [0]
RealVal是一个十六进制数字，代表我想要的值。
$ b
此外，这是在Python 2.7中的解决方案
I've seen a few questions about this already, but none that I read helped me actually understand why what I am trying to do is failing.
So I have a bunch of floating point values, and they have different precisions. Some are 0.1 others are 1.759374, etc. And I want to format them so they are ALL in the form of "+0.0000000E+00" I tried doing
number = '%1.7f' % oldnumber
but that didn't work. I thought what I was telling it to do was "one digit perfor the decimal point, and 7 after, float" but it doesn't work. I'm not really getting the examples in the docs, which don't seem to even bother with "before and after decimal point" issues, and I didn't find a question that was about before and after decimal point fixing.
Now, I know that some of my numbers are 0.0437 or similar, and I want them to appear as 4.3700000E-02 or something. I was sort of hoping it would do the E bit on it's own, but if it doesn't how do I do it?
Here is the exact line I have:
RealValConv = '%1.7g' % struct.unpack('!f', RealVal.decode('hex'))[0]
RealVal is a hex number that represents the value I want.
Also, this is in Python 2.7
>>> '{:.7e}'.format(0.00000000000000365913456789)
'3.6591346e-15'
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