如何抛出一个403错误的Apache CXF - Java的

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问题描述

我使用基于具有拦截以下code。检查时返回true，我想抛出一个403错误：

I am using the following code based on having an interceptor. When check returns true I want to throw a 403 error:

    @Override
    public void handleMessage(Message arg0) throws Fault {


        HttpServletRequest request = context.getHttpServletRequest();
        if(check(request)){
        // currently not working
                throw "Fault";
        }

我想抛出一个403错误。我怎么去这样做，从这个情况呢？

I want to throw a 403 error. How do I go about doing that from this situation?

我有点困惑如何投错的作品。

I am a little confused about how "throws fault" works.

任何帮助是pciated AP $ P $

Any help is appreciated

推荐答案

CXF将默认状态code至500的故障，但你可以将其设置<一个href=\"http://cxf.apache.org/javadoc/latest/org/apache/cxf/interceptor/Fault.html#setStatus$c$c%28int%29\">Fault.setStatus$c$c.例如：

CXF will default the status code to 500 for a Fault, but you can set it with Fault.setStatusCode. For example

Fault fault = new Fault(new Exception("Exception message"));
fault.setStatusCode(403);
throw fault;

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