通过PHP上传ZIP文件和UNZIP ftp文件夹

问题描述

我想制作一个表格，您可以在其中填写FTP登录服务器并获得上载ZIP文件的选项.该脚本的工作方式不同于我要执行UNZIP上传文件的最后一部分(UNZIP文件).有谁知道这是什么问题? TIA

I want to make a form where you can fill FTP login server and get option to upload ZIP file. The script works apart from the last part (UNZIP the file) I want to perform UNZIP uploaded file. Does anyone know what is the problem? TIA

<?php
if (isset($_POST['Submit'])) {
$ftp_server = $ftp = $_POST['ftp'];
$ftp_user_name = $username = $_POST['username'];
$ftp_user_pass = $password = $_POST['password'];


 if (!empty($_FILES['upload']['name'])) {
$ch = curl_init();

$file1 = $localfile = $_FILES['upload']['name'];
$fp = fopen($file1, 'r');

$file = '/htdocs/file.zip';
// set up basic connection
$conn_id = ftp_connect($ftp_server);

// login with username and password
$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass);

// try to upload $file
if (ftp_fput($conn_id, $file, $fp, FTP_ASCII)) {
    echo "Successfully uploaded ftp://".$username.":".$password."@".$ftp.$file."\n";

    $zip = new ZipArchive;
    $zip->open($file);
    $zip->extractTo('ftp://'.$username.':'.$password.'@'.$ftp.'/htdocs');
    $zip->close();

} else {
    echo "There was a problem while uploading $file\n";
}

// close the connection and the file handler
ftp_close($conn_id);
fclose($fp);
 }
}
?>

    <?php if(isset($error)){ echo $error; } ?>
        <form action="upload.php" method="post" enctype="multipart/form-data">
            <div>
                <label for="upload">Select file</label>
                <input name="upload" type="file" />
                <br> Ftp Server:
                <br>
                <input type="text" name="ftp" value="<?php if(isset($ftp)){ echo $ftp; } ?>">
                <br> Username:
                <br>
                <input type="text" name="username" value="<?php if(isset($username)){ echo $username; } ?>">
                <br> Password:
                <br>
                <input type="text" name="password" value="<?php if(isset($password)){ echo $password; }else{ echo '123456';} ?>">

                <input type="submit" name="Submit" value="Upload" />
            </div>
        </form>

错误

警告:ZipArchive :: close():中的无效或未初始化的Zip对象 第30行的C:\ xampp \ htdocs \ upload.php

Warning: ZipArchive::close(): Invalid or uninitialized Zip object in C:\xampp\htdocs\upload.php on line 30

推荐答案

ZipArchive不支持URL包装器.

The ZipArchive does not support URL wrappers.

反正您的代码没有多大意义:

And your code does not make much sense anyway:

• 您首先将$localfile作为/htdocs/file.zip

$file = '/htdocs/file.zip';
ftp_fput($conn_id, $file, $fp, FTP_ASCII)

然后您尝试打开/htdocs/file.zip，因为它是本地文件

And then you try to open /htdocs/file.zip, as it it were a local file

$zip->open($file);

但是这样的本地文件不存在.

But such local file does not exists.

然后尝试将不存在的文件提取到FTP URL.而且不支持.

And then you try to extract that non existing file to FTP URL. And that's not supported.

请参见 ZipArchive :: open():支持流包装器.它是关于open的，但是如果open不支持包装器，则extactTo也不会(这是一种更难以支持的方式).请参见 cmb的评论:

See ZipArchive::open(): support stream wrappers. It's about open, but if open does not support wrappers, the extactTo won't either (it's a way more difficult to support). See a comment by cmb:

但是，ZipArchive :: open()不是该文件系统的函数 问题.

However, ZipArchive::open() is not a filesystem function for that matter.

所以，实际上，这不是错误，甚至也不是文档中的文档错误. 严格意义上讲.因此，我将更改为功能请求.

So, actually, this is not a bug, not even a documentation bug in the strict sense. Therefore I'm changing to feature request.

由于您的代码是错误的，很难猜测您实际上在尝试做什么.我可以想象这两种可能性.

As your code is just wrong, its difficult to guess, what you are actually trying to do. I can imagine these two possibilities.

• 您想将ZIP文件上传到FTP服务器并在那里解压缩.只是无法在ZIP服务器上解压缩ZIP文件.

您想将本地ZIP提取到FTP服务器.尽管在ZipArchive:extractTo调用中似乎可以使用URL包装器，但事实并非如此.如上所示.也没有其他方法可以使用PHP中的一些简单的单行代码将本地ZIP文件提取到FTP服务器.

You wanted to extract a local ZIP to FTP server. While it may seem that it's possible with use of URL wrapper in the ZipArchive:extractTo call, it's not. As I've shown above. Nor there is any other way to extract local ZIP file to FTP server with some simple one-liner in PHP.

您所能做的就是在本地(在Web服务器上)提取ZIP文件.然后将其逐个文件上传到FTP服务器.

All you can do, is to extract the ZIP file locally (on the web server); and then upload it file-by-file to the FTP server.

• 创建一个临时文件夹，然后在其中提取(ZipArchive::extractTo)ZIP存档.

将临时文件夹上传到FTP服务器.

Upload the temporary folder to the FTP server.

请参见 PHP-ftp_put +复制整个文件夹结构.

删除临时文件夹.

还请注意，您使用ASCII模式上传文件. ZIP格式为二进制.通过以ASCII模式上载二进制文件，会损坏它.

Also note that you upload the file using ASCII mode. A ZIP format is binary. By uploading binary file in ASCII mode, you damage it.

ftp_fput($conn_id, $file, $fp, FTP_ASCII);

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