问题描述
我有两个类，基类在Obj-c中，子类在Swift中。
I have two classes, the base class is in Obj-c and the subclass is in Swift.
Obj-c类使用新的XCode 7的轻量级通用功能定义如下：
The Obj-c class uses new XCode 7's lightweight generic feature defined as follows:
@interface BaseController<T: SFObject *> : UIViewController
@property(nonatomic, strong) T model;
@end
这适用于Obj-c子类。
That works fine for Obj-c subclasses.
现在对于Swift，如果我像往常一样定义泛型类型，我会收到以下错误：
Now for Swift if I define the generic type as I usually do I get the following error:
我的第二个类定义如下：
My second class is defined as follows:
class SwiftController: BaseObjcController<SFUser> {
}
任何帮助将不胜感激。
谢谢。
Any help would be appreciated.Thanks.
推荐答案
来自：
除了这些Foundation集合类，Objective-C
Swift忽略了轻量级泛型。使用
轻量级泛型的任何其他类型都被导入到Swift中，好像它们是
unparameterized。
Aside from these Foundation collection classes, Objective-C lightweight generics are ignored by Swift. Any other types using lightweight generics are imported into Swift as if they were unparameterized.
所以这是目前不可能。正如您从
生成的界面助手视图中看到的那样，您的Objective-C类被导入
到Swift为
So this is not possible at present. As you can see from the"Generated Interface" assistant view, your Objective-C class is importedto Swift as
public class BaseController : UIViewController {
public var model: SFObject!
}
这也在Apple开发者论坛中讨论过：
This was also discussed in the Apple Developer Forum:
- Objective-C generics not visible from Swift?
随意提交增强错误报告！
Feel free to file an enhancement bug report!
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