Bash-如何将每一行放在引号内

问题描述

我想将每行放在引号内，例如:

I want to put each line within quotation marks, such as:

abcdefg
hijklmn
opqrst

转换为:

"abcdefg"
"hijklmn"
"opqrst"

如何在Bash shell脚本中执行此操作?

How to do this in Bash shell script?

推荐答案

使用 awk

awk '{ print "\""$0"\""}' inputfile

使用纯bash

while read FOO; do
   echo -e "\"$FOO\""
done < inputfile

其中inputfile是一个包含不带引号的行的文件.

where inputfile would be a file containing the lines without quotes.

如果文件中有空行，则 awk 绝对是可行的方法:

If your file has empty lines, awk is definitely the way to go:

awk 'NF { print "\""$0"\""}' inputfile

NF告诉awk仅在字段数"大于零(行不为空)时才执行打印命令.

NF tells awk to only execute the print command when the Number of Fields is more than zero (line is not empty).

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