如何从文件C ++用科学记数法读取浮点数？

问题描述

我有这种格式的文件：

-0.0064785667 0.73900002 0.028505694 4.7858757e-39 315 218
-0.0051828534 0.73900002 0.028505694 4.6936954e-39 316 218
-0.0038818798 0.73799998 0.028467119 5.1546736e-39 317 218
-0.0025879198 0.73799998 0.028467119 5.6160217e-39 318 218
-0.0012939599 0.73799998 0.028467119 6.4461411e-39 319 218

我使用此代码阅读：

using namespace std;

ifstream inputFile;

//Opens data file for reading.
inputFile.open(filePath.c_str());

//Creates vector, initially with 0 points.
vector<Point> data(0);
float temp_x,temp_y,temp_z,rgb=0,discard_1=0,discard_2=0;

//Read contents of file till EOF.
while (inputFile.good()){

    inputFile >> temp_x >> temp_y >> temp_z >> rgb >> discard_1 >> discard_2;

    data.push_back(Point(temp_x,temp_y,temp_z,rgb));

}

if (!inputFile.eof())
    if (inputFile.fail()) cout << "Type mismatch during parsing." << endl;
    else cout << "Unknow problem during parsing." << endl;

//Close data file.
inputFile.close();

阅读类型不匹配的科学记数法浮动的结果。

Reading the scientific notation float results in a type mismatch.

我怎样才能阅读所有数字，包括科学记数法浮？

How can I read all the numbers including the scientific notation float?

推荐答案

这个问题可能是你在─循环。从不使用 while（inputFile.good（））。使用这样的：

The problem is probably your while-loop. Never use while(inputFile.good()). Use this:

while (inputFile >> temp_x >> temp_y >> temp_z
                 >> rgb >> discard_1 >> discard_2) {}

的以一个不同的问题解释了原因。您可能也有兴趣，这表明一个更优雅的解决方案。

This answer to a different question explains why. You might also be interested in this answer, which suggests a more elegant solution.

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