XNA - 傍克隆 - 反思球时撞到墙？

本文介绍了XNA - 傍克隆 - 反思球时撞到墙？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 我试图让球反弹了我的用户界面的顶部和底部的'墙'创建2D傍克隆时的感觉。 这是我的Game.cs I'm trying to make the ball bounce off of the top and bottom 'Walls' of my UI when creating a 2D Pong Clone.This is my Game.cspublic void CheckBallPosition(){ if (ball.Position.Y == 0 || ball.Position.Y >= graphics.PreferredBackBufferHeight) ball.Move(true); else ball.Move(false); if (ball.Position.X < 0 || ball.Position.X >= graphics.PreferredBackBufferWidth) ball.Reset();} 目前，我在我的Ball.cs At the moment I'm using this in my Ball.cs public void Move(bool IsCollidingWithWall) { if (IsCollidingWithWall) { Vector2 normal = new Vector2(0, 1); Direction = Vector2.Reflect(Direction,normal); this.Position += Direction; Console.WriteLine("WALL COLLISION"); } else this.Position += Direction; } 它的工作原理，但我使用的是手动输入正常和我想知道如何计算正常屏幕？ 推荐答案好了，这是我将如何处理它Well, this is how I would handle itpublic void CheckBallPositionAndMove(){ if (ball.Position.Y <= 0 || ball.Position.Y >= graphics.PreferredBackBufferHeight) ball.HandleWallCollision(); ball.Move(); if (ball.Position.X < 0 || ball.Position.X >= graphics.PreferredBackBufferWidth) ball.Reset();}//In Ball.cs:private void HandleWallCollision(Vector2 normal){ Direction.Y *= -1; //Reflection about either normal is the same as multiplying y-vector by -1}private void Move(){ this.Position += Direction;} 然而，使用这种 请注意离散碰撞检测，你等到球已经移过顶后/屏幕下方来检测碰撞; 发生帧之间的碰撞可能是noticably关，尤其是当球快速移动。这是尤其的一个问题，如果你正在使用这种碰撞检测方法检测碰撞桨，因为如果球移动速度不够快，这是可能的球通过桨向右移动！ Note however that using this "discrete" collision detection, you wait until after the ball has moved past the top/bottom of the screen to detect a collision; collisions that occur "between" frames may be noticably off, especially if the ball is moving fast. This is especially a problem if you are using this collision-detection method to detect collision with a paddle, since, if the ball is moving fast enough, it is possible for the ball to move right through the paddle!对这个问题的解决方法是使用了被称为连续碰撞检测。 CCD通常比显著离散的碰撞检测更加复杂;幸运的是，乒乓球是很简单的，这样做CCD只会稍微复杂一些。不过，你仍然会需要高中代数扎实抓好以求解方程。The solution to this problem is to use what is known as Continuous Collision Detection. CCD is usually significantly more complex than discrete collision detection; fortunately, pong is simple enough that doing CCD would only be slightly more complex. However, you'd still need a solid grasp of high-school algebra to solve the equations.如果你仍然有兴趣，有CCD的一个很好的解释在这个讲座和的这个GameDev文章去多一点深入。也有许多的问题与它左右。If you are still interested, there is a good explaination of CCD in this lecture, and this GameDev article goes a bit more in-depth. There are also many questions relating to it on SO. 这篇关于XNA - 傍克隆 - 反思球时撞到墙？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！