问题描述
假设我要绘制x^2.我可以按以下方式使用curve().
Suppose I want to plot x^2. I can use curve() as follows.
curve(x^2, -5, 5)
但是，我希望轴经过(0，0).我可以做以下事情:
However, I would like the axes to go through (0, 0). I could do something as follows:
curve(x^2, -5, 5, axes=FALSE)
axis(1, pos=0)
axis(2, pos=0)
abline(h=0)
abline(v=0)
最后我得到类似下面的内容，看起来不错.但是我唯一的抱怨是，这种绘制轴的方式使实际轴(例如x轴的-4和4之间的线段)比右侧和左侧的线段更粗. y轴也是如此.我想知道是否有更好的方法来绘制轴.谢谢！
And I end up getting something like below, which looks OK. But the only gripe I have is that this way of plotting axes makes the actual axes - for example the segment between -4 and 4 of the x-axis - thicker than the segments to the right side and the left side. The same goes with the y axis. I wonder if there is a better way of plotting the axes. Thank you!
推荐答案
默认情况下，axis()自动计算刻度线的位置，但是您可以使用at参数手动定义它们.因此，解决方法可能类似于:
By default, axis() computes automatically the tick marks position, but you can define them manually with the at argument. So a workaround could be something like :
curve(x^2, -5, 5, axes=FALSE)
axis(1, pos=0, at=-5:5)
axis(2, pos=0)
哪个给:
问题在于您必须手动确定每个刻度线的位置.更好的解决方案是使用axTicks函数(默认情况下使用该函数)来计算它们，但使用自定义的axp参数调用该函数，该参数允许您分别指定刻度的最小，最大和间隔数在轴上:
The problem is that you have to manually determine the position of each tick mark. A slightly better solution would be to compute them with the axTicks function (the one used by default) but calling this one with a custom axp argument which allows you to specify respectively the minimum, maximum and number of intervals for the ticks in the axis :
curve(x^2, -5, 5, axes=FALSE)
axis(1, pos=0, at=axTicks(1,axp=c(-10,10,10)))
axis(2, pos=0)
哪个给:
这篇关于如何将x和y轴的截距放在(0，0)处并将x和y轴延伸到图的边缘的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！