我如何使用Jersey JSON POJO支持？

问题描述

我有一个对象，我想在JSON中作为RESTful资源提供服务。我打开了Jersey的JSON POJO支持（在web.xml中）：

I have an object that I'd like to serve in JSON as a RESTful resource. I have Jersey's JSON POJO support turned on like so (in web.xml):

<servlet>
    <servlet-name>Jersey Web Application</servlet-name>
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
        <param-value>true</param-value>
    </init-param>

    <load-on-startup>1</load-on-startup>
</servlet>

但是当我尝试访问该资源时，我得到了这个例外：

But when I try to access the resource, I get this exception:

SEVERE: A message body writer for Java type, class com.example.MyDto, and MIME media type, application/json, was not found
SEVERE: Mapped exception to response: 500 (Internal Server Error)
javax.ws.rs.WebApplicationException
...

我正在尝试提供的课程并不复杂，只有一些公共最终字段和一个设置所有这些字段的构造函数。这些字段都是字符串，基元，与此类似的类或其列表（我尝试使用普通列表而不是通用列表< T> s，无济于事）。有谁知道是什么给出的？谢谢！

The class that I'm trying to serve isn't complicated, all it's got are some public final fields and a constructor that sets all of them. The fields are all strings, primitives, classes similar to this one, or Lists thereof (I've tried using plain Lists instead of generic List<T>s, to no avail). Does anyone know what gives? Thanks!

Java EE 6

Java EE 6

泽西岛1.1.5

GlassFish 3.0.1

GlassFish 3.0.1

推荐答案

Jersey-json有一个JAXB实现。您获得该异常的原因是因为您没有已注册，或更具体地说是。您需要在提供商中注册适当的上下文：

Jersey-json has a JAXB implementation. The reason you're getting that exception is because you don't have a Provider registered, or more specifically a MessageBodyWriter. You need to register a proper context within your provider:

@Provider
public class JAXBContextResolver implements ContextResolver<JAXBContext> {
    private final static String ENTITY_PACKAGE = "package.goes.here";
    private final static JAXBContext context;
    static {
        try {
            context = new JAXBContextAdapter(new JSONJAXBContext(JSONConfiguration.mapped().rootUnwrapping(false).build(), ENTITY_PACKAGE));
        } catch (final JAXBException ex) {
            throw new IllegalStateException("Could not resolve JAXBContext.", ex);
        }
    }

    public JAXBContext getContext(final Class<?> type) {
        try {
            if (type.getPackage().getName().contains(ENTITY_PACKAGE)) {
                return context;
            }
        } catch (final Exception ex) {
            // trap, just return null
        }
        return null;
    }

    public static final class JAXBContextAdapter extends JAXBContext {
        private final JAXBContext context;

        public JAXBContextAdapter(final JAXBContext context) {
            this.context = context;
        }

        @Override
        public Marshaller createMarshaller() {
            Marshaller marshaller = null;
            try {
                marshaller = context.createMarshaller();
                marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
            } catch (final PropertyException pe) {
                return marshaller;
            } catch (final JAXBException jbe) {
                return null;
            }
            return marshaller;
        }

        @Override
        public Unmarshaller createUnmarshaller() throws JAXBException {
            final Unmarshaller unmarshaller = context.createUnmarshaller();
            unmarshaller.setEventHandler(new DefaultValidationEventHandler());
            return unmarshaller;
        }

        @Override
        public Validator createValidator() throws JAXBException {
            return context.createValidator();
        }
    }
}

这会查找 @XmlRegistry ，包含 @XmlRootElement 带注释的POJO。

This looks up for an @XmlRegistry within the provided package name, which is a package that contains @XmlRootElement annotated POJOs.

@XmlRootElement
public class Person {

    private String firstName;

    //getters and setters, etc.
}

然后在同一个包中创建一个ObjectFactory：

then create an ObjectFactory in the same package:

@XmlRegistry
public class ObjectFactory {
   public Person createNewPerson() {
      return new Person();
   }
}

使用 @Provider 已注册，泽西岛应为您资源中的编组提供便利：

With the @Provider registered, Jersey should facilitate the marshalling for you in your resource:

@GET
@Consumes(MediaType.APPLICATION_JSON)
public Response doWork(Person person) {
   // do work
   return Response.ok().build();
}

这篇关于我如何使用Jersey JSON POJO支持？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！