本文介绍了无法使用urllib2将content-type设置为application/json的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这个小宝宝:
import urllib2
import simplejson as json
opener = urllib2.build_opener()
opener.addheaders.append(('Content-Type', 'application/json'))
response = opener.open('http://localhost:8000',json.dumps({'a': 'b'}))
产生以下请求(如ngrep所示):
Produces the following request (as seen with ngrep):
sudo ngrep -q -d lo '^POST .* localhost:8000'
T 127.0.0.1:51668 -> 127.0.0.1:8000 [AP]
POST / HTTP/1.1..Accept-Encoding: identity..Content-Length: 10..Host: localhost:8000..Content-Type: application/x-www-form-urlencoded..Connection: close..User-Agent:
Python-urllib/2.7....{"a": "b"}
我不想要那个Content-Type: application/x-www-form-urlencoded
.我明确地说我想要('Content-Type', 'application/json')
I do not want that Content-Type: application/x-www-form-urlencoded
. I am explicitely saying that I want ('Content-Type', 'application/json')
这是怎么回事?!
推荐答案
如果要设置自定义标头,则应使用Request
对象:
If you want to set custom headers you should use a Request
object:
import urllib2
import simplejson as json
opener = urllib2.build_opener()
req = urllib2.Request('http://localhost:8000', data=json.dumps({'a': 'b'}),
headers={'Content-Type': 'application/json'})
response = opener.open(req)
这篇关于无法使用urllib2将content-type设置为application/json的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!