问题描述
我的脚本使用了命令行参数，它需要将此参数传递给curl命令，并用双引号引起来。这是到目前为止我尝试过的简化版本：
My script is taking the command line argument and it needs to pass this to curl command in double quotes. This is the simplified version of what I tried so far:
json=$1;
echo $json;
curl -X POST -d'{ asin：\ $ json\， template： bolt， version： 1d}'-H内容类型：application / json http：// someURL
但是它不起作用。请帮助
But its not working. Please help
推荐答案
$-单引号字符串中的$变量不会扩展。 -d 参数需要用双引号引起来，或者至少 $ json 部分需要：
$-variables in single quoted strings don't get expanded. The -d argument needs be in double quotes, or at least the $json part needs to be:
curl -X POST -d '{"asin":"'"$json"'", "template":"bolt","version":"1d"}' -H "Content-Type: application/json" http://someURL
'-终止单引号字符串，然后跟随 $ json ，然后开始'
'-terminates the single-quoted string, then "$json" follows, and then ' starts an adjacent single quoted string.
$ json 变量不应扩展为包含未转义双精度字符的字符串引号或生成的json将被破坏。
The "$json" variable shouldn't expand to a string containing unescaped double quotes or the resulting json will be broken.
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