问题描述
将一个表视为table2
,我想在此表update
上添加一个trigger
作为
Consider a table as table2
, i like to add a trigger
on this table update
as
select Num into num from table1 where ID=new.id;
BEGIN
DECLARE done int default false;
DECLARE cur1 CURSOR FOR select EmailId from users where Num=num;
DECLARE continue handler for not found set done = true;
OPEN cur1;
my_loop: loop
fetch cur1 into email_id;
if done then
leave my_loop;
end if;
//send mail to all email id.
end loop my_loop;
close cur1;
END;
有什么简单的方法可以在有评论的地方写东西吗?要将电子邮件发送到从表users
中检索到的所有电子邮件ID.
Is there any simple method to write in the place commented? To send a email to all the email id retrieved from table users
.
我在XAMPP(phpmyadmin)中使用MySQL.
I am using MySQL in XAMPP(phpmyadmin).
推荐答案
我反对该解决方案.将发送电子邮件的负担放在数据库服务器中可能会非常糟糕.
I'm against that solution. Putting the load of sending e-mails in your Database Server could end very bad.
我认为,您应该做的是创建一个表,将要发送的电子邮件排入队列,并有一个过程检查是否有要发送的电子邮件,如果发送成功,则将其发送.
In my opinion, what you should do is create a table that queues the emails you would want to send and have a process that checks if there are emails to be sent and send them if positive.
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