问题描述
在我的Java code，我想44100赫兹的WAV文件转换为8000 Hz的WAV文件。我知道，我必须低通滤波器，然后抽取（+插值）（DSP的理论），但我不想从头开始实现它。
In my Java code, I would like to convert a WAV file of 44100 Hz to a WAV file of 8000 Hz. I know that I have to low-pass filter and then decimate (+interpolate) (the DSP theory) but I do not want to implement it from scratch.
我要寻找一个库，可以有效地做到这一点。你知道有什么？
I am looking for a library that can efficiently do it. Do you know any?
我能够从缓冲区中读取wav文件到一个缓冲区，也写入wav文件到文件，如果它会更容易。
I am able to read wav files into a buffer and also write wav files from buffer to file if it will make it easier.
推荐答案
您应该看看一个包装，可以处理各种转换工作（包括音频重采样）非常有效。
You should look at FMJ. It provides a wrapper for ffmpeg which can handle all sorts of conversion work (including audio resampling) very efficiently.
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