问题描述
我使用的 CakePHP的框架2.2.2。
我想创建一个个性化的URL的用户。例如，如果用户输入的用户名= pragnesh 然后他们可以访问我的网站，如： http://pragnesh.mylocalhost.com ，相同blinksale.com
我的网址： http://mylocalhost.com/test/users/front_home
我想在访问它： http://test.mylocalhost.com/users/ front_home
我的网址： http://mylocalhost.com/test/setting/pages
http://test.mylocalhost.com/setting/pages ：可以访问
任何网址： http://mylocalhost.com/test/xxxxx/xxxxx
http://test.mylocalhost.com/xxxxx/xxxxx ：可以访问
或
网址： http://mylocalhost.com/users/front_home?site=test
我想在访问它： http://test.mylocalhost.com/users/ front_home
我的网址： http://mylocalhost.com/setting/pages?site=测试
http://test.mylocalhost.com/setting/pages ：可以访问
任何网址： http://mylocalhost.com/xxxxx/xxxxx?site=测试
http://test.mylocalhost.com/xxxxx/xxxxx ：可以访问
我的问题可能是我的CakePHP的2.2的网站不工作的子域但目前还没有答案公布。
我已经试过低于code \程序\ webroot.htaccess
！ 的RewriteCond％{QUERY_STRING} ^（[^＆放大器;] *放大器;）*网站= [^＆安培] +
的RewriteCond％{HTTP_HOST}！^ WWW \ .mylocalhost.com
的RewriteCond％{HTTP_HOST}（[A-ZA-Z0-9] +）\。mylocalhost.com
重写规则^（[^ \。] *）。PHP $ /$1.php?user=%1 [QSA，L，R]
主机名＃捕获第一部分
的RewriteCond％{HTTP_HOST} ^（[^。] +）\。mylocalhost \ .COM $ [NC]
＃确保网站=查询参数是不存在的
的RewriteCond％{QUERY_STRING}（^ |＆安培）！网站= [NC]
＃改写当前的URI？网站= backererence＃1的主机名
重写规则^％{REQUEST_URI}？网站=％1 [L，QSA]
但两者不是为我工作。
我的根.htaccss文件
＆LT; IfModule mod_rewrite.c＆GT;
RewriteEngine叙述上
重写规则^ $应用程序/ Web根目录/ [L]
重写规则（。*）的应用程序/ Web根目录/ $ 1 [L]
＆LT; / IfModule＆GT;
\ app.htaccess
＆LT; IfModule mod_rewrite.c＆GT;
RewriteEngine叙述上
重写规则^ $ Webroot公司/ [L]
重写规则（。*）根目录/ $ 1 [L]
＆LT; / IfModule＆GT;
\程序\ webroot.htaccess
＆LT; IfModule mod_rewrite.c＆GT;
RewriteEngine叙述上
的RewriteCond％{} REQUEST_FILENAME！-d
的RewriteCond％{} REQUEST_FILENAME！-f
重写规则^（。*）$的index.php [QSA，L]
＆LT; / IfModule＆GT;
在httpd.conf虚拟主机
＆LT;虚拟主机*：80＆GT;
的DocumentRootE：/ XAMPP / htdocs中/ bsale
服务器名mylocalhost.com
ServerAlias * .mylocalhost.com
＆LT;目录C：/ XAMPP / htdocs中/ bsale＆GT;
订购允许，拒绝
所有允许
＆LT; /目录＆GT;
＆LT; /虚拟主机＆GT;
主机文件
127.0.0.1 mylocalhost.com
127.0.0.1 * .mylocalhost.com
您可以留下您的.htaccess作为默认CakePHP的/的.htaccessCakePHP的/应用/的.htaccessCakePHP的/应用程序/ Web根目录/的.htaccess
您需要的虚拟主机就像现在都指向您的应用程序。
你真正需要考虑的是应用程序/配置/ routes.php文件
看看就行，上面写着：
CakePlugin ::航线（）;
所以，那一刻之前，你可以做任何你需要（有路由）。让我们设想一个用户JOHNDOE有 http://johndoe.yourapp.com/
从URL中获取的子域，是这样的：
array_shift（（爆炸（subdomain.my.com'））。）;
使用：
$ _ SERVER ['HTTP_HOST']
路由器::连接（'/用户/ front_home'，阵列（'控制'=＆GT;'用户'，'行动'=＆GT;front_home'，$ yourSubDomain））;
或者刚刚离开路由器单独检测的子域名在你的AppController，并在任何地方使用它在你的应用程序。
I am using Cakephp framework 2.2.2.
I want to create a personalized URL for the user. For example, if a user enters username=pragnesh,then they can access my site like: http://pragnesh.mylocalhost.com, same as in blinksale.com
My URL: http://mylocalhost.com/test/users/front_home
I want to access it at: http://test.mylocalhost.com/users/front_home
My URL: http://mylocalhost.com/test/setting/pages
can be accessed at: http://test.mylocalhost.com/setting/pages
any URL: http://mylocalhost.com/test/xxxxx/xxxxx
can be accessed at : http://test.mylocalhost.com/xxxxx/xxxxx
OR
URL: http://mylocalhost.com/users/front_home?site=test
I want to access it at: http://test.mylocalhost.com/users/front_home
My URL: http://mylocalhost.com/setting/pages?site=test
can be accessed at: http://test.mylocalhost.com/setting/pages
any URL: http://mylocalhost.com/xxxxx/xxxxx?site=test
can be accessed at: http://test.mylocalhost.com/xxxxx/xxxxx
My question may be possible duplicate of My cakephp 2.2 site not working on subdomainbut there is no answer posted.
I have tried below code in \app\webroot.htaccess
RewriteCond %{QUERY_STRING} !^([^&]*&)*site=[^&]+
RewriteCond %{HTTP_HOST} !^www\.mylocalhost.com
RewriteCond %{HTTP_HOST} ([a-zA-Z0-9]+)\.mylocalhost.com
RewriteRule ^([^\.]*).php$ /$1.php?user=%1 [QSA,L,R]
# capture first part of host name
RewriteCond %{HTTP_HOST} ^([^.]+)\.mylocalhost\.com$ [NC]
# make sure site= query parameter isn't there
RewriteCond %{QUERY_STRING} !(^|&)site= [NC]
# rewrite to current URI?site=backererence #1 from host name
RewriteRule ^ %{REQUEST_URI}?site=%1 [L,QSA]
but both not working for me.
my root .htaccss file is
<IfModule mod_rewrite.c>
RewriteEngine on
RewriteRule ^$ app/webroot/ [L]
RewriteRule (.*) app/webroot/$1 [L]
</IfModule>
\app.htaccess
<IfModule mod_rewrite.c>
RewriteEngine on
RewriteRule ^$ webroot/ [L]
RewriteRule (.*) webroot/$1 [L]
</IfModule>
\app\webroot.htaccess
<IfModule mod_rewrite.c>
RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^(.*)$ index.php [QSA,L]
</IfModule>
Virtual Host in httpd.conf
<VirtualHost *:80>
DocumentRoot "E:/xampp/htdocs/bsale"
ServerName mylocalhost.com
ServerAlias *.mylocalhost.com
<Directory "C:/xampp/htdocs/bsale">
Order allow,deny
Allow from all
</Directory>
</VirtualHost>
HOST FILE
127.0.0.1 mylocalhost.com
127.0.0.1 *.mylocalhost.com
You can leave your .htaccess as in the defaultcakephp/.htaccesscakephp/app/.htaccesscakephp/app/webroot/.htaccess
You will need the virtual host like now have pointing at your app.
What you really need to look at is the app/Config/routes.php
take a look at the line that says:
CakePlugin::routes();
So, before that moment you can do anything you need (with routes).Lets imagine a user johndoe has http://johndoe.yourapp.com/
Get the subdomain from the url, something like this:
array_shift((explode(".",'subdomain.my.com')));
using:
$_SERVER['HTTP_HOST']
Router::connect('/users/front_home', array('controller' => 'users', 'action' => 'front_home', $yourSubDomain));
Or just leave the router alone and detect the subdomain in your AppController, and use it anywhere in your app.
这篇关于URL重写创建子域在CakePHP中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！