本文介绍了为什么我的代码返回此错误:mysql_query() access denied for user ''@'localhost' (using password no)的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
<div class="items"><ul><li><?php echo $msg[$lang]["gtd"];?><div class="text"><强><?php$result = mysql_query("SELECT id FROM games WHERE `starttime` > ".(time()-86400));回声 mysql_num_rows($result);?></strong>
此代码的第 8 行返回错误:
mysql_query() 用户 ''@'localhost' 访问被拒绝(使用密码 no)".https://stackoverflow.com/search?q=mysql_query%28%29+access+denied+for+user+%40%27localhost%27
这在 SO 和 谷歌.
您似乎根本没有连接到数据库.包括以下内容(当然，使用您的凭据填充函数参数):
$connection = mysql_connect('localhost', 'db_username', 'db_password')或者 die('连接问题:' .mysql_error());mysql_select_db('your_database', $connection);</div>
<div class="items">
<ul>
<li>
<?php echo $msg[$lang]["gtd"]; ?>
<div class="text">
<strong>
<?php
$result = mysql_query("SELECT id FROM games WHERE `starttime` > ".(time()-86400));
echo mysql_num_rows($result);
?></strong>
</div>
</li>
Line 8 of this code returns the error:
mysql_query() access denied for user ''@'localhost' (using password no)".
https://stackoverflow.com/search?q=mysql_query%28%29+access+denied+for+user+%40%27localhost%27
This is an extremely popular issue on both SO, as well as Google.
You don't appear to have connected to the database at all. Include the following (populating the function arguments with your credentials, of course):
$connection = mysql_connect('localhost', 'db_username', 'db_password')
or die('connection problem:' . mysql_error());
mysql_select_db('your_database', $connection);
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