问题描述
我尝试以下code
#include <stdio.h>
int main(void)
{
typedef static int sint;
sint i = 10;
return 0;
}
和命中以下错误：
error: multiple storage classes in declaration specifiers
当我提到的C99规范，我才知道，的typedef 是存储类。
When I referred the C99 specification, I came to know that typedef is a storage class.
6.7.1 Storage-class specifiers
Syntax
storage-class-specifier:
typedef
extern
static
auto
register
Constraints: At most, one storage-class specifier may be
given in the declaration specifiers in a declaration
Semantics: The typedef specifier is called a ‘‘storage-class specifier’’
for syntactic convenience only;
（基于一些互联网搜索和交叉在C99规格指各部分），我能找到的唯一解释是语法上的方便才使语法简单。
我在找一些理由/解释上的类型名称怎么能有存储类说明？
I'm looking for some justification/explanation on how can a type name have storage class specifier?
不有意义有一个code像的typedef静态INT SINT;
Doesn't it make sense to have a code like typedef static int sint;?
或我在哪里去了？！
推荐答案
是的typedef 是一个存储类说明符如您在标准中。在某种程度上这是一个语法上的便利，但它是经过深思熟虑的，你可以有的typedef 的或的比较明显的存储类说明符之一。
Yes, typedef is a storage-class-specifier as you found in the standard. In part it's a grammatical convenience, but it is deliberate that you can either have typedef or one of the more "obvious" storage class specifiers.
一个typedef声明的类型创建一个别名。
A typedef declaration creates an alias for a type.
在声明静态INT X; 类型X 是 INT 。 静态无关的类型。
In a declaration static int x; the type of x is int. static has nothing to do with the type.
（想想看，如果你把 X ，＆安培的地址; X 的类型为int * 为int * Y =＆放大器; X; 将是合法的，因为会静态INT * Z =＆放大器; X ，但后者静态影响存储类以Z ，并且是独立于存储的类 X ）
(Consider that if you take the address of x, &x has type int*. int *y = &x; would be legal as would static int *z = &x but this latter static affects the storage class of z and is independent of the storage class of x.)
如果像这样被允许的静态将不得不为没有对象被宣布无效。被别名的类型只是 INT 。
If something like this were allowed the static would have no effect as no object is being declared. The type being aliased is just int.
typedef static int sint;
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