Java - 使用选项执行程序，如 ls -l

问题描述

1. 在 Java 中，如何执行带有选项的 linux 程序，如下所示:

1. In Java, how do I execute a linux program with options, like this:

ls -a(选项是-a)，

和另一个:./myscript name=john age=24

我知道如何执行命令，但不能执行选项.

I know how to execute a command, but cannot do the option.

推荐答案

需要执行一个外部进程，看博客生成器几乎可以回答你的问题，而http://javaeva href="http://javaeva href="http://java..com.au/2011/12/java-tip-of-day-using-processbuilder-to.html" rel="nofollow">使用 ProcessBuilder 进行系统调用

You need to execute an external process, take a look at ProcessBuilder and just because it almost answers your question, Using ProcessBuilder to Make System Calls

更新示例

我直接从列表示例中提取并修改了它，以便我可以在我的 PC 上进行测试并且它运行良好

I ripped this straight from the list example and modified it so I could test on my PC and it runs fine

private static void copy(InputStream in, OutputStream out) throws IOException {
    while (true) {
        int c = in.read();
        if (c == -1) {
            break;
        }
        out.write((char) c);
    }
}

public static void main(String[] args) throws IOException, InterruptedException {

//        if (args.length == 0) {
//            System.out.println("You must supply at least one argument.");
//            return;
//        }

    args = new String[] {"cmd", "/c", "dir", "C:\"};

    ProcessBuilder processBuilder = new ProcessBuilder(args);
    processBuilder.redirectErrorStream(true);

    Process process = processBuilder.start();
    copy(process.getInputStream(), System.out);
    process.waitFor();
    System.out.println("Exit Status : " + process.exitValue());
}

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