如何在Windows中使用子进程

问题描述

我正在尝试将结果或函数 runcmd 保存在变量 Result 中.这是我尝试过的: 导入子进程

I am trying to save the result or function runcmd in the variable Result.Here is what I have tried: import subprocess

def runcmd(cmd):
  x = subprocess.Popen(cmd, stdout=subprocess.PIPE)
  Result = x.communicate(stdout)
  return Result
runcmd("dir")

运行代码时，我得到以下结果:

When I run ths code, I get this result:

Traceback (most recent call last):
  File "C:\Python27\MyPython\MyCode.py", line 7, in <module>
    runcmd("dir")
  File "C:\Python27\MyPython\MyCode.py", line 4, in runcmd
    x = subprocess.Popen(cmd, stdout=subprocess.PIPE)
  File "C:\Python27\lib\subprocess.py", line 679, in __init__
errread, errwrite)
  File "C:\Python27\lib\subprocess.py", line 893, in _execute_child
    startupinfo)
WindowsError: [Error 2] The system cannot find the file specified

该如何解决?

推荐答案

我认为您正在寻找的是os.listdir()

I think what you are looking for is os.listdir()

查看操作系统模块以获取更多信息

一个例子:

>>> import os
>>> l = os.listdir()
>>> print (l)
['DLLs', 'Doc', 'google-python-exercises', 'include', 'Lib', 'libs', 'LICENSE.txt', 'NEWS.txt', 'python.exe', 'pythonw.e
xe', 'README.txt', 'tcl', 'Tools', 'VS2010Cmd.lnk']
>>>

您还可以将输出读入列表:

You could also read the output into a list:

result = []
process = subprocess.Popen('dir',
    shell=True,
    stdout=subprocess.PIPE,
    stderr=subprocess.PIPE )
for line in process.stdout:
    result.append(line)
errcode = process.returncode
for line in result:
    print(line)

这篇关于如何在Windows中使用子进程的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！