问题描述
我与使用字符串的二维数组的程序工作（可能不是明智的开始，但EH），我想要写一个函数，这些阵列（一个假设数组1 ），使一个独立的副本，并将其返回（假设数组2）。然而，当我再更改数组2的值，它似乎在数组1中得到体现。
I'm working with a program that uses two-dimensional arrays of Strings (probably not that smart to begin with, but eh), and I'd like to write a function that takes one of these arrays (let's say array1), makes an independent copy, and returns it (let's say array2). However, when I then change a value in array2, it seems to be reflected in array1.
我目前的功能看起来是这样的：
My function currently looks something like this:
public static String[][] copy(String[][] matrix, int n) {
String[][] out = new String[n+1][n+1];
for (int i = 0; i < n+1; i++)
for (int j = 0; j < n+1; j++) {
if(matrix[i][j] != null) {
String cp = new String(matrix[i][j]);
out[i][j] = cp;
}
}
return out;
}
我宣布一个新的字符串数组，然后通过它遍历单独复制每个值。如果没有工作，我甚至试过明确声明从每个旧字符串新的字符串，并把数组中来代替。
I declare a new array of Strings, and then iterate through it, copying each value individually. When that didn't work, I even tried explicitly declaring a new string from each old string and putting that in the array instead.
谁能告诉我，我要去哪里错了？
Can anyone tell me where I'm going wrong?
推荐答案
您方法看起来像它应该工作，虽然在正作为参数传递使其脆，使用输入数组的长度字段会更好，你甚至可以处理不规则数组的方式。
Your method looks like it should work, though passing in n as a parameter makes it brittle, using the input array's length field would be better, and you could even handle jagged arrays that way.
制作内容的拷贝是没有必要的，因为字符串不能被改变 - 这导致的主要问题：你在做什么样的变化，似乎在副本中得到体现？向我们展示code，它这样做了。
Making a copy of the contents is not necessary, since Strings cannot be changed - which leads to the main question: What kind of changes are you making that seem to be reflected in the copy? Show us the code that does this.
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