本文介绍了如何在MySQL存储过程中计算这些日期差和乘法?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试在mysql中实现一个过程,该过程基于计算返回天数.输入购买日期(added_date),然后完成计算.应该相对简单一些,但我似乎无法使它正常工作.我不确定这是否适合选择语句",如果这非常简单,这是我第一次在程序中运行,我对此表示歉意.

I am trying to implement a procedure within mysql that returns the number of days based on a calculation. The purchase date (added_date) is passed in and then the calculation is done. Should be relatively straight forward but I cannot seem to get it to work. I am not sure if this is an appropriate situation for a "select statement" and I apologize if this is extremely simple but this is my first run at procedures.

如果有人可以告诉我该怎么办,将不胜感激.

If somebody could please tell me what should i do so, it would be much appreciated.

谢谢!

我有一个名为"计算"的表(表3),该表包含字段"elap_yend"(整数),该字段在调用存储过程之前一直为空.

I have a table called "calculation"(TABLE 3) that contains the field "elap_yend " (int) which is currently empty until the stored procedure is called.

表1:

cid     parent_cat      category_name            category_life
22        0             Office Equipment-M'         1080
23        0             Office Equipment-O'         1800
24        0             F & F'                      3600
25        0             Staff assets',              1800
27        0             Motor vehicle',             2880
28        0             Air conditioner'            5400
29        0             Land & Building',           2160
30        0             Temporary Partition         365
31        0             Electrical Fittings         3600
32        0             Generator'                  5400
33        0             Software'                   1800
34        0             Computer-N'                 2160
35        24            chair'                      3600

Tble 2:

pid    cid    product_name      product_price   added_date  cgst  sgst igst  total      depre
60      22    RHFL\test\001         20000       2018-11-02  1800  1800  0     23600     o
61      27    RHFL\test\002         13500       2018-11-02  2345  2345  0     15930     12
62      29    RHFL\test\003         65000       2018-11-02  2345  2345  0     76700     12
63      31    RHFL\test\004         10000       2018-11-02  2345  2345  0     1180      12
64      24    RHFL\test\005         10000       2018-11-02  2345  2345  0     11800      1
65      24    RHFL\test\006         13500       2018-11-02  2345  2345  0     15930     12
66      34    RHFL\test\007         13500       2018-11-02  2345  2345  0     15930     12
67      22    RHFL\test\008         65004       2018-11-02  2345  2345  0     76704     12
68      25    RHFL\test\009         10000       0000-00-00  2345  2345  0     11800     12
69      22    RHFL\test\010         65000       0000-00-00  2345  2345  0     76700     10
                                                                                        70

表3:存储过程的输出应反映在下表中:

Table 3: output of the stored procedure should reflect in the below table:

   end_date   elap_yend rem_days depre_cur cur_wdv depre_next next_wdv acc_depre
   2018-11-02     0                 0      0         0          0        0

输出计算:

上面是输出为零的样本.这不是确切的输出,但是每当我调用存储过程时,都应该在计算以下进行这些操作.

Above is the sample output with zero. It is not the exact output but whenever i am calling the stored procedure it should do these below calculation.

   DELIMITER $$

CREATE PROCEDURE calculationTemp(
    in  till_yend date,
    )
BEGIN
    DECLARE till_yend date;

    SELECT datediff(now(),added_date) INTO till_yend
    FROM products

    IF till_yend > 0 THEN
 SET till_yend = select datediff(now(),added_date) from products;
        ELSEIF till_yend < 0 THEN
        SET till_yend = 0;
    END IF;
 insert into calculationTemp
END$$

计算方式:

过去的年末: 直到每年31/March/xxxx为止elapsed_yend = add_date(来自产品表(No:2)).

Elapsede year end : elapsed_yend = added_date(from products table (No:2)) till every year 31/March/xxxx.

这两个日期之间的天数

remaining_days = category_life-(addd_date(从产品(No:1))到日期之间的日期差)

remaining_days = category_life - (date difference between added_date(from products (No:1)) till date)

category_life(来自类别表(编号:1))例如:移动设备的使用寿命为1080天.

category_life(from categories table (No:1))Ex:mobile it's life will be 1080 days.

当年折旧:depreciation_cur =(depre/category_life)* elapsed_yend

Current Year depreciation:depreciation_cur = (depre/category_life)*elapsed_yend

  • 当年的书面价值:

  • Current Year Written down value:

current_wdv = depre-depreciation_cur

current_wdv = depre - depreciation_cur

下一年的折旧: depreciation_next =(depre/category_life)* D D =每年01/April/xxxx到end_date之间的天差(来自计算表)

Next Year depreciation : depreciation_next = (depre / category_life) * D D = days difference between every year 01/April/xxxx till end_date(from calculation table)

下一年的书面价值:

next_wdv = current_wdv-depreciation_next

next_wdv = current_wdv - depreciation_next

累计折旧:

accumulate_depre =折旧_cur +折旧_pext

accumulate_depre = depreciation_cur + depreciation_next

推荐答案

我的答案在这里发布,以获取有关改善我的商店流程的任何想法.谢谢!!!

Got My answer posting here to get any idea regarding to improve my store procedure. Thank You!!!

 BEGIN
    DECLARE cur_depre,cur_wtvalue,next_depre,next_wtvalue,accum_depre,pro_loss double(20,2);
    DECLARE days,next_diff int;

    CREATE TABLE IF NOT EXISTS calc AS (SELECT p.pid,p_date,days,next_diff,cur_depre,cur_wtvalue,next_depre,next_wtvalue,accum_depre,pro_loss,c.cid,p.added_date,c.category_life,p.depre,p.sale_status,p.sale_date,p.sale_amount from products p,products d,categories c WHERE p.pid=d.pid AND p.cid=c.cid
     );
     INSERT INTO calc (PID)
    SELECT PID FROM products WHERE PID NOT IN (SELECT PID FROM calc);
    UPDATE calc set days = datediff(p_date,added_date);
    UPDATE calc set days = 0 WHERE datediff(p_date,added_date) < 0;
    UPDATE calc set next_diff = datediff(sale_date,DATE_ADD(p_date, INTERVAL 1 DAY) );
    UPDATE calc set next_diff = datediff('2019-03-31',added_date) WHERE added_date>p_date;
    UPDATE calc set cur_depre = (depre/category_life)*datediff(p_date,added_date);

    UPDATE calc set cur_depre = 0 where (depre/category_life)*datediff(p_date,added_date)<0;

    UPDATE calc set cur_wtvalue =(depre-(depre/category_life)*datediff(p_date,added_date));

    UPDATE calc set cur_wtvalue = 0 WHERE added_date>p_date;

    UPDATE calc set next_depre =( (depre/category_life)*datediff(sale_date,DATE_ADD(p_date, INTERVAL 1 DAY) )) where added_date < p_date;

    UPDATE calc set next_depre =( (depre/category_life) * datediff('2019-03-31',added_date)) WHERE added_Date > p_date;

    UPDATE calc SET next_wtvalue = depre -(depre/category_life)*datediff(p_date,added_date) - (( (depre/category_life)*datediff(sale_date,DATE_ADD(p_date, INTERVAL 1 DAY) )) );
    UPDATE calc SET next_wtvalue = depre - (( (depre/category_life) * datediff('2019-03-31',added_date)))  WHERE added_date>p_date;

    UPDATE calc SET accum_depre = ((depre/category_life)*datediff(p_date,added_date))+( (depre/category_life)*datediff(sale_date,DATE_ADD(p_date, INTERVAL 1 DAY) )) ;
    UPDATE calc SET accum_depre =( (depre/category_life) * datediff('2019-03-31',added_date))  WHERE added_Date > p_date;

    UPDATE calc SET pro_loss = sale_amount-(depre -(depre/category_life)*datediff(p_date,added_date) - (( (depre/category_life)*datediff(sale_date,DATE_ADD(p_date, INTERVAL 1 DAY) )) ) );

    UPDATE calc SET pro_loss = 0 WHERE sale_status=0;
    SELECT * from calc;

    END

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08-13 17:45