Android的Sugar ORM找不到我的列名

问题描述

好吧，我正在尝试选择entitie_id = *some id*

Well I'm trying to select all entities where entitie_id = *some id*

我使用以下规则进行此操作:

I do this with this rule:

List<NodeSugar> nodesugars = NodeSugar.find(NodeSugar.class, "entitie_id = ? ", String.valueOf(nodeid));

我知道我应该得到一些结果，但会出现错误.这个错误:

I know I should get some results back and I get an error.this error:

E/SQLiteLog﹕ (1) no such column: entitie_id

我知道该列存在是因为我可以在代码的不同部分进行设置.

I know the column exists because I can set it in a different part of code.

我要去哪里错了?

推荐答案

您应该可以使用"entitieid"进行查询.

You should be able to query with "entitieid".

Sugar ORM在表中创建列时会进行一些转换.这是一个基本示例:

Sugar ORM does some conversion when it creates the columns in the tables. Here is a basic example:

String firstName; //creates column first_name
int entitie_id;   //creates column entitieid

文档仅指定从驼峰大小写到下划线分隔的转换.我不得不弄清楚另一个.

The documentation only specifies the conversion from camel case to underscore separation. I had to figure the other one out.

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