本文介绍了如何仅删除字符串中大写字母的变音符号的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要删除字符串中大写字母的变音符号.示例:ÉlectroniqueCaméras=> ElectroniqueCaméras(仅修改了É,Caméras中的é保持不变)

I need to remove diacritics from uppercase characters in a string.Example : Électronique Caméras => Electronique Caméras (only the É is modified, é in Caméras remains as it is)

我正在使用以下方法,该方法仅从大写字母中删除变音符号,但是重建的字符串看起来像这样-Electronique Came?ras(é丢失了).如何正确重建字符串?

I am using the following method, which removes diacritics only from the uppercase letters, but the reconstructed string looks like this - Electronique Came?ras (é is lost). How can I reconstruct the string properly?

public static String removeDiacriticsFromUppercaseLetters(String input)
    {
        if (input == null)
              return input;
        String normalized= Normalizer.normalize(input, Normalizer.Form.NFD);

        StringBuilder newString = new StringBuilder();
        newString.append(normalized.charAt(0));

        for (int i=1;i<normalized.length();++i)
        {
            //Check if this diacritic is for an uppercase letter, if yes, skip
            if (Character.isUpperCase(normalized= .charAt(i-1)) && Character.getType(normalized.charAt(i)) == Character.NON_SPACING_MARK){
              continue;
            }
            else{
              newString.append(normalized.charAt(i));
            }
        }
        return newString.toString();
    }

谢谢

推荐答案

尝试以下方法:

public static String removeDiacriticsFromUppercaseLetters(String input)
{
    if (input == null)
        return null;

    String normalized = Normalizer.normalize(input, Normalizer.Form.NFD);

    StringBuilder newString = new StringBuilder();
    boolean checkDiacritics = false;

    for (int i = 0; i < normalized.length(); ++i)
    {
        char ch = normalized.charAt(i);

        if (checkDiacritics)
        {
            if (Character.getType(ch) == Character.NON_SPACING_MARK)
                continue;

            checkDiacritics = false;
        }

        if (Character.isUpperCase(ch))
            checkDiacritics = true;

        newString.append(ch);
    }

    //return newString.toString();
    return Normalizer.normalize(newString.toString(), Normalizer.Form.NFC);
}

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08-04 12:57