将Pandas DataFrame中的2列与.loc进行比较

问题描述

我想比较具有值(1)的两列并列出满足此条件的行.这是我的代码:

I want to compare two columns with value (1) and list rows that satisfy this condition. Here is my code:

import pandas as pd

df = pd.DataFrame({'col':[0,1,1,0,1],
                   'col2':[0,1,0,1,0],
                   'ord':[0,1,2,3,4]
})

df1 = df.loc[df['col'] == 1 & df['col2'] == 1]

print(df1)

预期输出:

   col  col2  ord
0    1     1    1

但是我得到了:

ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

推荐答案

添加括号是因为&运算符的优先级:

Add parentheses because priority precedence of & operator:

df1 = df.loc[(df['col'] == 1) & (df['col2'] == 1)]

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