Python:以随机顺序删除一对重复的字符串

问题描述

我有一个如下列表

[('generators', 'generator'), ('game', 'games'), ('generator', 'generators'), ('games', 'game'), ('challenge', 'challenges'), ('challenges', 'challenge')]

对('game', 'games')和('games', 'game')有点相同，但是顺序不同.

Pairs ('game', 'games') and ('games', 'game') are kind of same but they are in different order.

我想要实现的输出

[('generators', 'generator'), ('games', 'game'), ('challenge', 'challenges')]

如何从上面的列表中删除配对?

How can I remove pairs as such from above list ?

任何建议，深表感谢.

推荐答案

您可以在集合中使用无序的可哈希数据结构. frozenset()是您的朋友在这里:

You can use an unordered hashable data structure within a set. frozenset() is your friend here:

In [7]: {frozenset(i) for i in your_list}
Out[7]: 
{frozenset({'generator', 'generators'}),
 frozenset({'game', 'games'}),
 frozenset({'challenge', 'challenges'})}

请注意，为避免循环遍历列表，最好在创建列表时首先进行此操作.

Note that in order to avoid looping over your list it's better to do this at the first place while creating your list.

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