从一个python传递到另一个

从一个python传递到另一个

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如何将视频流从一个python传递到另一个?

本文介绍了如何将视频流从一个python传递到另一个?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

在我以前的文章中，我们找到了一种将图像文件从一个python传递到另一个python的方法:将视频数据从一个python脚本传递到另一个

In my previous post, we found a way to pass an image file from one python to another:pass video data from one python script to another

我现在正在尝试通过视频(连续图像):

I am now trying to pass a video (successive images):

write.py 

import sys
import numpy as np
import cv2
from PIL import Image
import io
import time

while True:
    img = cv2.imread('cat.jpg')
    bimg = cv2.imencode('.jpg',img)[1]
    sys.stdout.buffer.write(bimg)
    sys.stdout.flush()
    time.sleep(1)

read.py:

import sys
from PIL import Image
import io
import cv2
import numpy as np
from io import BytesIO

while True:
    data = sys.stdin.buffer.read()
    img_np = cv2.imdecode(np.frombuffer(BytesIO(data).read(), np.uint8), cv2.IMREAD_UNCHANGED)
    cv2.imshow('image', img_np)
    cv2.waitKey(0)

如果我将write.py数据输出到终端，则会打印出来.如果我手动将数据传递给read.py，则会被读取.但是将它们放在一起( python3 write.py | python3 read.py )，它就会挂起.write.py只写一次，而read.py似乎从来没有得到它.

If I output the write.py data to terminal, it prints. If I manually hand data to read.py that gets read. But put them together (python3 write.py | python3 read.py) and it just hangs. write.py just writes once, and read.py never seems to get it.

我的猜测是，读取的代码正在等待写入的代码结束".在包装数据包并将其称为图像之前.尽管是这种情况，但我认为冲洗可以解决该问题.

My guess is that the read code is waiting for the write code to "end" before it wraps up the data package and calls it an image. Though if that were the case, I would think it that doing a flush would fix it.

推荐答案

我想我明白了.在 read.py 中， sys.stdin.buffer.read()读取并等待，直到 stdin 管道关闭但写入.py 从未真正关闭其 stdout ，这是因为 while True 循环所致.这个概念验证的简化示例起作用:

I think I figured it out. In read.py, sys.stdin.buffer.read() reads and waits until the stdin pipe is closed but write.py never actually closes its stdout because of the while True loop. This proof of concept simplified example works:

write.py 

import sys
import time

sys.stdout.buffer.write(b"Hello world")
sys.stdout.buffer.flush()

# Note if we comment out the code bellow it works again
while True:
    # Keep this alive but don't have `while True:pass`
    # because my computer might crash :D
    time.sleep(10)

和 read.py 

import sys

with open("output.txt", "w") as file:
    file.write(sys.stdin.read())

这也将挂起，并且永远不会实际将任何内容写入"output.txt" .如果我们从 write.py 中删除 while True 循环，则该代码将不再挂起，并且"Hello World" 将被写入"output.py" ，因为完成 write.py 的写操作将关闭其进程，并关闭管道.要解决此问题，我建议将 read.py 更改为以下内容:

This will also hang and will never actually write anything to "output.txt". If we remove the while True loop from write.py the code will no longer hang and "Hello World" will be written to "output.py" because when write.py is finished writing it will close its process and that will close the pipe. To fix this issue I recommend changing read.py to something like this:

import sys

while True:
    with open("output.txt", "a") as file:
        file.write(sys.stdin.read(1))

解决方案:

write.py 

import sys
import time

MAX_FILE_SIZE = 16 # bytes

msg = b"Hello world"

# Tell `reader.py` that it needs to read x number of bytes.
length = len(msg)
# We also need to tell `read.py` how many bytes it needs to read.
# This means that we have reached the same problem as before.
# To fix that issue we are always going to send the number of bytes but
# We are going to pad it with `0`s at the start.
# https://stackoverflow.com/a/339013/11106801
length = str(length).zfill(MAX_FILE_SIZE)
sys.stdout.buffer.write(length.encode())

sys.stdout.buffer.write(msg)
sys.stdout.buffer.flush()

# We also need to tell `read.py` that it was the last file that we send
# Sending `1` means that the file has ended
sys.stdout.buffer.write(b"1")
sys.stdout.buffer.flush()

# Note if we comment out the code bellow it works again
while True:
    # Keep this alive but don't have `while True:pass`
    # because my computer might crash :D
    time.sleep(10)

和 read.py 

import sys
import time

MAX_FILE_SIZE = 16 # bytes

while True:
    time.sleep(1) # Make sure `write.py` has sent the data
    # Read `MAX_FILE_SIZE` number of bytes and convert it to an int
    # So that we know the size of the file comming in
    length = int(sys.stdin.buffer.read(MAX_FILE_SIZE))
    time.sleep(1) # Make sure `write.py` has sent the data

    # Here you can switch to a different file every time `writer.py`
    # Sends a new file
    with open("output.txt", "wb") as file:
        file.write(sys.stdin.buffer.read(length))

    file_ended = sys.stdin.buffer.read(1)
    if file_ended == b"1":
        # File has ended
        break
    else:
        # We are going to start reading again for the next file:
        pass

该解决方案的工作原理如下:

The solution works like this:

  1. 发送文件大小
  2. 发送实际文件数据
  3. 发送一个字节，告知 read.py 是否应该期待另一个文件
  1. Send the size of the file
  2. Send the actual file data
  3. Send a byte that tell read.py if it should be expecting another file or not

对于第1部分，我们只是将文件的长度编码为一个字符串，该字符串的前面用0填充.注意:确保 MAX_FILE_SIZE 大于最大文件的大小(较大的数字会稍微降低性能).对于第3部分，如果我们发送"1" ，则意味着不再有文件要发送.否则， reader.py 将等待并接受下一个文件.因此 write.py 将变为:

For part 1, we just encode the length of the file as a string that is padded with 0s at the front. Note: Make sure that the MAX_FILE_SIZE is larger than the size of the largest file (large numbers will slightly decrease the performance). For part 3, if we send a "1" it will mean that there are no more files to be sent. Otherwise reader.py will wait and accept the next file. So write.py will become:

from math import log
import time
import sys
import cv2


MAX_FILE_SIZE = 62914560 # bytes
MAX_FILE_SIZE = int(log(MAX_FILE_SIZE, 2)+1)


def write_file(buffer, data, last_file=False):
   # Tell `reader.py` that it needs to read x number of bytes.
   length = len(data)
   # We also need to tell `read.py` how many bytes it needs to read.
   # This means that we have reached the same problem as before.
   # To fix that issue we are always going to send the number of bytes but
   # We are going to pad it with `0`s at the start.
   # https://stackoverflow.com/a/339013/11106801
   length = str(length).zfill(MAX_FILE_SIZE)
   with open("output.txt", "w") as file:
      file.write(length)
   buffer.write(length.encode())

   # Write the actual data
   buffer.write(data)

   # We also need to tell `read.py` that it was the last file that we send
   # Sending `1` means that the file has ended
   buffer.write(str(int(last_file)).encode())
   buffer.flush()


while True:
    img = cv2.imread("img.jpg")
    bimg = cv2.imencode(".jpg", img)[1]
    # Call write_data
    write_file(sys.stdout.buffer, bimg, last_file=False)
    # time.sleep(1) # Don't need this

和 read.py 将变为:

from io import BytesIO
from math import log
import numpy as np
import time
import cv2
import sys


MAX_FILE_SIZE = 62914560 # bytes
MAX_FILE_SIZE = int(log(MAX_FILE_SIZE, 2)+1)


def read(buffer, number_of_bytes):
    output = b""
    while len(output) < number_of_bytes:
        output += buffer.read(number_of_bytes - len(output))
    assert len(output) == number_of_bytes, "An error occured."
    return output


def read_file(buffer):
    # Read `MAX_FILE_SIZE` number of bytes and convert it to an int
    # So that we know the size of the file comming in
    length = int(read(buffer, MAX_FILE_SIZE))

    # Here you can switch to a different file every time `writer.py`
    # Sends a new file
    data = read(buffer, length)

    # Read a byte so that we know if it is the last file
    file_ended = read(buffer, 1)

    return data, (file_ended == b"1")


while True:
    print("Reading file")
    data, last_file = read_file(sys.stdin.buffer)
    img_np = cv2.imdecode(np.frombuffer(BytesIO(data).read(), np.uint8),
                          cv2.IMREAD_UNCHANGED)
    cv2.imshow("image", img_np)
    cv2.waitKey(0)

    if last_file:
        break;

这篇关于如何将视频流从一个python传递到另一个?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！

07-23 04:38
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