使用旋转的xlabel在Seaborn Python中绘制条形图

问题描述

如何在Seaborn中绘制没有任何统计信息的简单条形图?数据集就是名称和值.

How can I plot a simple bar graph in Seaborn without any statistics? The data set is simply names and values.

import pandas
df = pandas.DataFrame({"name": ["Bob Johnson", "Mary Cramer", "Joe Ellis"], "vals": [1,2,3]})

我想将其绘制为条形图，其中xlabels从 name 列中拉出，y轴值从 vals 中拉出，并且x轴标签旋转45度.如何做呢?像这样使用 sns.barplot :

I would like to plot this as a bar graph with xlabels pulled from name column and y-axis values from vals and have x-axis labels rotated 45 degrees. How can it be done? Using sns.barplot like:

sns.barplot(x="name", y="vals", data=df)

将计算此处不相关的统计信息.

will compute statistics that are not relevant here.

推荐答案

您的意思是那样的( set_xticklabels 方法):

You mean like that (set_xticklabels approach):

import pandas

df = pandas.DataFrame({"name": ["Bob Johnson", "Mary Cramer", "Joe Ellis"], "vals": [1,2,3]})
g = sns.barplot(x='name', y='vals', data=df)
g.set_xticklabels(g.get_xticklabels(), rotation=45)

---

或者 plt.xticks 方法可能会有所帮助:

import pandas
import matplotlib.pylab as plt

df = pandas.DataFrame({"name": ["Bob Johnson", "Mary Cramer", "Joe Ellis"], "vals": [1,2,3]})

bar_plot = sns.barplot(x='name', y='vals', data=df)
plt.xticks(rotation=45)
plt.show()

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