使用 PIL 调整文件夹中所有图像的大小

问题描述

我可以一次调整一张图片的大小，但是如何以类似的方式调整一个文件夹中所有图片的大小?请帮帮我.

i'm able to resize each image one at a time,but how can I resize all images in one folder in a similar way? Please help me.

from PIL import Image
from resizeimage import resizeimage
    with open('test-image.jpeg', 'r+b') as f:
        with Image.open(f) as image:
            cover = resizeimage.resize_cover(image, [200, 100])
            cover.save('test-image-cover.jpeg', image.format)

推荐答案

更新: 现在使用 os.listdir() 而不是 glob.glob() 因为需要从原来的文件中生成新的文件名.代码现在将调整大小的图像与其原始文件和添加的后缀保存在同一文件夹中.

Updated: Now uses os.listdir() instead of glob.glob() because of the need generate new file names from the original. Code now saves the resized images in same folder with its original file plus an added suffix.

请注意，Image.open() 需要传递给它的文件路径，而不是打开的文件.

Note that Image.open() wants a file path passed to it, not an opened file.

import os
from PIL import Image
from resizeimage import resizeimage

img_folder = '/path/to/img_folder'
fileext = '.jpg'
suffix = '_RESIZED'

for img_filename in os.listdir(img_folder):
    filename, ext = os.path.splitext(img_filename)

    if ext == fileext:
        print(filename, ext)
        src_img_filepath = os.path.join(img_folder, img_filename)
        dst_img_filepath = os.path.join(img_folder, filename+suffix, ext)

        with Image.open(src_img_filepath) as image:
            cover = resizeimage.resize_cover(image, [200, 100])
            cover.save(dst_img_filepath, image.format)

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